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тАО12-10-2006 06:37 PM
тАО12-10-2006 06:37 PM
1234561|2007|2|28
4567891|2007|3|31
7897891|2007|4|5
9879871|2007|5|30
2578961|2007|6|25
...
..
.
where $2 is year $3 is month and $4 is day..
considering if today is 30may2007 I heed to have on my other file just one line:
9879871|2007|5|30
is that possible to bo done in ksh pleasee..
thanks a lot...
Solved! Go to Solution.
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тАО12-10-2006 06:59 PM
тАО12-10-2006 06:59 PM
Re: please help with kshell script..
how about:
grep -e '|2007|5|30' datafile
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тАО12-10-2006 07:21 PM
тАО12-10-2006 07:21 PM
Re: please help with kshell script..
or for a more generic solution:
#!/usr/bin/ksh
grep -e "$1|$2|$3" datafile
$ ./b.sh 2007 5 30
9879871|2007|5|30
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тАО12-10-2006 07:44 PM
тАО12-10-2006 07:44 PM
Re: please help with kshell script..
$ cat ./extract.sh
#!/usr/bin/sh
if [ $# != 4 ]
then
THIS_YEAR=$(date +%Y)
THIS_MONTH=$(date +%m)
THIS_DAY=$(date +%d)
MONTH=$(echo ${THIS_MONTH#0})
DAY=$(echo ${THIS_DAY#0})
grep "$THIS_YEAR|$MONTH|$DAY" $1
else
grep "$1|$2|$3" $4
fi
Try running it like this:
$ ./extract.sh 2007 2 28 ./infile
1234561|2007|2|28
or wait till the end of February and run it without parameters...
regards,
John K.
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тАО12-10-2006 07:55 PM
тАО12-10-2006 07:55 PM
Re: please help with kshell script..
I assume u want to get only the line corresponding to today's date
in other file.
If so then try this
$ awk -F \| -v a=`date "+%Y"` -v b=`date "+%m"` -v c=`date "+%d"` '$2==a&&$3==b&&$4==c {print $1}'
Thats all
-Santosh
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тАО12-10-2006 08:20 PM
тАО12-10-2006 08:20 PM
Re: please help with kshell script..
Sorry for a small mistake,
Pl. replace {print $1} with {print $0}
-Santosh
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тАО12-11-2006 01:00 AM
тАО12-11-2006 01:00 AM
Re: please help with kshell script..
1111119|2007|3|31
if dodays date is april 30 I need to take that line as well as a result..
for example: today is 28 feb 2007 I need to test next date..if next date is 1.something.2007 I need to have
that line as result as well..
for example if I have:
1111119|2007|2|28
1111119|2007|4|30
1111119|2007|12|31
1111119|2007|8|8
and let assume that today is june 30 2007 as an output I should have:
1111119|2007|2|28
1111119|2007|4|30
1111119|2007|12|31
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тАО12-11-2006 01:09 AM
тАО12-11-2006 01:09 AM
Re: please help with kshell script..
Can you please state your EXACT requirements?
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тАО12-11-2006 01:41 AM
тАО12-11-2006 01:41 AM
Re: please help with kshell script..
but if today is for example june 30, 2007
and my input file is like this:
8111319|2007|2|28
1112119|2007|4|30
7111119|2007|12|31
1231119|2007|8|8
script should check if next day is 1st in the month and output this:
8111319|2007|2|28
1112119|2007|4|30
7111119|2007|12|31
becouse february has 28 days...if today is for example 8 sept or 8 dec or any other month output should be like this:
1231119|2007|8|8
that means if I have bigger file:
1234561|2007|2|28
4567891|2007|3|31
7897891|2007|4|5
9879871|2007|5|30
1578961|2007|6|28
1897893|2007|10|28
7879871|2007|12|30
9578962|2007|12|28
and today is 28 of august:
output should be like this:
1234561|2007|2|28
1578961|2007|6|28
1897893|2007|10|28
9578962|2007|12|28
that means does not metter which month is it looks fot day..
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тАО12-11-2006 01:48 AM
тАО12-11-2006 01:48 AM
Re: please help with kshell script..
1) If the current day is the LAST DAY of the month, then look in the file for ANY LINES from the current year that occur on the last day of their respective months.
2) If the current day is some other time in the month, then look for lines from the current year from any month where the day equals today.
Is that accurate?