Command Question..

[allanm77]

Hi All,

I have a file which looks like this -

Allan M

Allan T

John H

Terry P

Harry P

I want to print the file as well as do a line count -

Allan M

Allan T

John H

Terry P

Harry P

5

Want to do this as fast as it can be done, for example if we are talking about 10 miliion lines.

Need to do this in one single command without ";".

Thanks,

Allan.

[James R. Ferguson]

Hi Allan:

# perl -ple '$n++;END{print $n}' file

Regards!

...JRF...

[allanm77]

Thanks JRF,

Tried but getting error -

Unrecognized character \xEF in column 19 at -e line 1

Allan.

[James R. Ferguson · Accepted solution]

Hi (again) Allan:

---

@allanm77 wrote:
Tried but getting error -

Unrecognized character \xEF in column 19 at -e line 1

---

Well, re-type what I posted.  However, here's an even shorter variation given your requirement:

perl -ple 'END{print $.}' file

...or if you prefer:

awk '{print};END{print NR}' file

Regards!

...JRF...

[H.Merijn Brand (procura]

Of course I like the perl solution, but what is wrong with good old plain fast default unix tools?

$ wc -l<file>>file

[Dennis Handly]

>but what is wrong with good old plain fast default unix tools?

Because there is no tool the both prints and gives that count.

(Unless you use nl(1) or cat(1) to number each line.)

[H.Merijn Brand (procura]

Ah, I misread the OP as that it was required to add the line count to the end of the file.

Mea culpa.