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тАО09-30-2007 03:36 PM
тАО09-30-2007 03:36 PM
Hi,
Today is Oct-1-2007, a Monday date. My script runs werid that is to start with getting the last Sunday date, then the Monday date before this Sunday date.
day1=`date "+%Y%m%d"`
day2=`date +%w`
if [ $day2 -eq 0 ]; then
sun_day=$day1
else
sun_day=`date +%Y%m%d-$day2|bc`
fi
mon_day=`date +%Y%m%d-$day2-6|bc`
echo $sun_day $mon_day
The result produced is:
20071000 20070994
Pls render help
Rita
Today is Oct-1-2007, a Monday date. My script runs werid that is to start with getting the last Sunday date, then the Monday date before this Sunday date.
day1=`date "+%Y%m%d"`
day2=`date +%w`
if [ $day2 -eq 0 ]; then
sun_day=$day1
else
sun_day=`date +%Y%m%d-$day2|bc`
fi
mon_day=`date +%Y%m%d-$day2-6|bc`
echo $sun_day $mon_day
The result produced is:
20071000 20070994
Pls render help
Rita
Solved! Go to Solution.
3 REPLIES 3
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тАО09-30-2007 05:57 PM
тАО09-30-2007 05:57 PM
Solution
What's weird? 20071001 - 1 = 20071000, and
20071001 - 1 - 6 = 20070994. You got what
you asked for.
The result of "date '+%Y%m%d'" is not an
ordinary decimal number, so you can't do
ordinary decimal arithmetic on it and get
a resonable answer, except by luck.
You might look at the suggestions for a
similar problem at:
http://forums1.itrc.hp.com/service/forums/questionanswer.do?threadId=1040167
20071001 - 1 - 6 = 20070994. You got what
you asked for.
The result of "date '+%Y%m%d'" is not an
ordinary decimal number, so you can't do
ordinary decimal arithmetic on it and get
a resonable answer, except by luck.
You might look at the suggestions for a
similar problem at:
http://forums1.itrc.hp.com/service/forums/questionanswer.do?threadId=1040167
- Tags:
- date arithmetic
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тАО09-30-2007 06:49 PM
тАО09-30-2007 06:49 PM
Re: Script with problem for getting dates
Hello Rita,
date '+%m %d %Y' |
{
read MONTH DAY YEAR
DAY=`expr "$DAY" - 1`
case "$DAY" in
0)
MONTH=`expr "$MONTH" - 1`
case "$MONTH" in
0)
MONTH=12
YEAR=`expr "$YEAR" - 1`
;;
esac
DAY=`cal $MONTH $YEAR | grep . | fmt -1 | tail -1`
esac
sun_day=$YEAR/$MONTH/$DAY
mon_day=`date +%Y/%m/%d`
echo $sun_day $mon_day
}
The result produced is:
2007/9/30 2007/10/01
Please modify above script further.
Thanks
date '+%m %d %Y' |
{
read MONTH DAY YEAR
DAY=`expr "$DAY" - 1`
case "$DAY" in
0)
MONTH=`expr "$MONTH" - 1`
case "$MONTH" in
0)
MONTH=12
YEAR=`expr "$YEAR" - 1`
;;
esac
DAY=`cal $MONTH $YEAR | grep . | fmt -1 | tail -1`
esac
sun_day=$YEAR/$MONTH/$DAY
mon_day=`date +%Y/%m/%d`
echo $sun_day $mon_day
}
The result produced is:
2007/9/30 2007/10/01
Please modify above script further.
Thanks
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тАО10-01-2007 05:15 AM
тАО10-01-2007 05:15 AM
Re: Script with problem for getting dates
A. Clay's script is great
Problem is fixed
Thank you for the prompt respond
Rita
Problem is fixed
Thank you for the prompt respond
Rita
- Tags:
- caljd
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