sed question

[Allanm]

Hi!

I want to add line y after line x in httpd.conf file but struggling with it...

line x #CustomLog logs/localhost/access_log combined

line y CustomLog "|/bin/cat - >> /apache/logs/localhost/access_log" combined

Can you suggest a sed one liner for this. Mine doesnt work and gives wierd behaviour -

sed '=#CustomLog logs\/localhost\/access_log combined= a\CustomLog \"\|\/bin\/cat \- \>\> \/apache\/logs\/localhost\/access_log\" combined' httpd.conf >> httpd.conf.2

Thanks,
Allanm

[Allanm]

Please Help!

[Peter Nikitka]

Hi,

if this is a one-timer, use vi.
If this has to be done in a script:

...
{
print "/CustomLog logs\/localhost\/access_log combined/a"
print 'CustomLog "|/bin/cat - >> /apache/logs/localhost/access_log" combined'
print '.\nw'
} | ed - http.conf
...

mfG Peter

PS: untested

[Bob E Campbell]

You have an interesting set of strings that are going to call for some escapes, but in general this would be done in sed as a straight append command:

sed -e '/^TargetString/a\
Appended string here'

Your string has so many quotes and slashes that it will take me a minute. If you do not need to match on the whole string that would certainly help.

[Bob E Campbell · Accepted solution]

sed -e '/^#CustomLog logs\/localhost\/access_log combined/ a\
CustomLog "|/bin/cat - >> /apache/logs/localhost/access_log combined"
'

[James R. Ferguson]

Hi:

You could do:

# perl -ne 'if (/^#CustomLog/) {print;print qq(INSERT_ > "SOME" < _LINE\n)} else {print}' file

...Notice that the line to be inserted actually looks like:

INSERT_ > "SOME" < _LINE

...that is, you are free to put any string you want in its place, thus, you want:

# perl -ne 'if (/^#CustomLog/) {print;print qq(CustomLog "|/bin/cat - >> /apache/logs/localhost/access_log" combined\n)} else {print}' file

Regards!

...JRF...

[Allanm]

Thanks All!!!