Multiple Telnet Sessions

[Darrell Albee]

Solution given on December 5 by Sridhar Bhaskarla was great however we have since had some people that do need multiple sessions. I have attached the script which was modified and inserted into our profile script to allow certain people multiple sessions. What is happening now is with the modifications the system is only letting someone with the ip address beginning with what is specified in the profile script multiple logins. Example: My ip address ends in 14.2 and if there are 3 people on that end in 14.22 and 14.24 and 14.17 then it does not let me on. How do I correct this problem?

[Jeff Machols]

try this

NO=`who -R |grep -x $IP|wc -l`

[Craig Rants]

The -x addition should work for you, you may also want to consider changing all the if/fi statements to one if/elif/elif../fi statement. That would probably work quicker for you down the line if your script keeps growing.

GL,
C

[harry d brown jr]

easy:

change your script to use grep:

#######
test=`echo $IP | grep -f ips.allow`
if [ "$test" != "" ]; then
BYPASS='Y'
fi
if [ "$IP" = "" ]; then
BYPASS='Y'
fi

#########
create a file called "ips.allow"::

172.31.17.1$
172.31.16.10$
DTS_TFLEX_TS01$
172.31.17.109$
172.31.17.5$

The "$" tells grep that it is the end of the line, so trailing characters will not match.


live free or die
harry

[harry d brown jr]

Darrell,

using my example as a stand alone script:

ips.allow:
172.31.17.1$
172.31.16.10$
DTS_TFLEX_TS01$
172.31.17.109$
172.31.17.5$

test:
#!/usr/bin/ksh
#
BYPASS='N'
read IP
test=`echo $IP | grep -f ips.allow`
if [ "$test" != "" ]; then
BYPASS='Y'
fi
if [ "$IP" = "" ]; then
BYPASS='Y'
fi
echo $BYPASS


here is a test:

# ./test
172.31.17.11
N
# ./test
172.31.17.1
Y
#

To test for "null" use "ctrl-d" to simulate it, as carriage return is a \n.

live free or die
harry