Arithemetic operator on a file/output

[vvsha]

Hi

Can any one help me for the following query.

I have one file which has the entries like as follows

Mar 23 09 abcd
Mar 24 09 abcd
Mar 24 11 pqrs
Mar 25 13 wxyz
Mar 25 13 wxyz
Mar 26 22 abcd
Mar 26 01 abcd
Mar 26 02 abcd
Mar 27 03 wxyz
Mar 27 06 wxyz
Mar 28 06 wxyz
Mar 29 07 pqrs
Mar 29 07 pqrs

I just want to find out the values which is greater than "Mar 25"

On the basis of second column value I want to print?

output should be all the entries greater than or equal to "25"

How can we use operators here in this example?

Please help me on this query

[Heiner E. Lennackers · Accepted solution]

You can do it with awk:

awk '$2 >= 25 { print $0 }' /path/to/yourfile

will print out what you want to the standard output

HeL

[OldSchool]

Basically, you've asked 3 separate, though seemingly related, questions, both in this thread and here:

http://forums11.itrc.hp.com/service/forums/questionanswer.do?threadId=1215980

Given your sample data:

Mar 23 09 abcd
Mar 24 09 abcd
Mar 24 11 pqrs
Mar 25 13 wxyz
Mar 25 13 wxyz
Mar 26 22 abcd
Mar 26 01 abcd
Mar 26 02 abcd
Mar 27 03 wxyz
Mar 27 06 wxyz
Mar 28 06 wxyz
Mar 29 07 pqrs
Mar 29 07 pqrs
Mar 29 07 pqrs

You've listed various, often contradictory requirements, such as "remove duplicates", field 2 > 25 and so forth. In the case of "remove duplicates", you don't specify what constitutes a duplicate (ie. field 4 the same, fields 1-4 match exactly and so forth).

A clear, concise definition of the requirement would go a long way towards getting the correct answer.

[vvsha]

Thank you very much