if statment

[kamal_15]

please help

this line return error. idon't know how to write it

------------------------------------
if [ $var1 | awk ' {print $2} ' = " " ]
then
echo "anything"
fi
-------------------------------------

i want to check if second part of variable is empty?

thanks

[RAC_1]

what does variable look like??

[Tony Scully_2]

From what you say there are two parts to the variable? Is it not possible to have 2 variables and just test the seconf one?

[kamal_15]

var1 contain this tring
---------------------
tabname anyname
---------------------

[Tony Scully_2]

try

echo "$var1" before the pipe?

[Tony Scully_2]

Actually, don't htink that helps because if the seond part is blank then no $2 will get set.

Sorry

[RAC_1]

seond_var=$(awk -F " " '{print $2}' ${var})

[[ ${second_var} = "" ]]
then
echo "no second_var"
fi

[kamal_15]

many thankx
but i tryed to execute it in one statment

if i find solution i will tell u

thankx again

[Tony Contratto]

This should do it:

if [ "$(echo ${var1} | awk '{print $2}')" = "" ]
then
echo "anything"
fi


--
Tony

[Taulant Shamo]

Hi Kamal,

Try this I could work.


if (test $var1 = `awk '{print $2}'`=" ")
than echo "anything"
exit
fi

Taulant