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    <title>topic Re: RAID 5 in Operating System - Microsoft</title>
    <link>https://community.hpe.com/t5/operating-system-microsoft/raid-5/m-p/3982184#M8001</link>
    <description>woo, I would never say raid 5 uses one disk for parity. the parity is distributed across the disks. If only the one disk had all the parity data you would be up a creek if you lost just that disk.</description>
    <pubDate>Mon, 16 Apr 2007 10:43:53 GMT</pubDate>
    <dc:creator>Court Campbell</dc:creator>
    <dc:date>2007-04-16T10:43:53Z</dc:date>
    <item>
      <title>RAID 5</title>
      <link>https://community.hpe.com/t5/operating-system-microsoft/raid-5/m-p/3982182#M7999</link>
      <description>I have an HP ProLiant ML370 Series server with 3 72GB hard disks devided into 2 partitions C &amp;amp; D.&lt;BR /&gt;If i enter to the device manager i can see only two hard disks installed while physically i have 3.&lt;BR /&gt;I need an explanation to that please.&lt;BR /&gt;&lt;BR /&gt;Also the RAM capacity is 4 GB. If i enter to the BIOS i can see the correct capacity of the RAM while if i right click the "My Computer" and go to properties i can see the RAM capacity is 3.25 GB&lt;BR /&gt;Kindly explain.&lt;BR /&gt;&lt;BR /&gt;Regards, &lt;BR /&gt;Abdul R. Arab&lt;BR /&gt;&lt;BR /&gt;&lt;BR /&gt;</description>
      <pubDate>Mon, 16 Apr 2007 09:37:16 GMT</pubDate>
      <guid>https://community.hpe.com/t5/operating-system-microsoft/raid-5/m-p/3982182#M7999</guid>
      <dc:creator>Abdul R. Arab</dc:creator>
      <dc:date>2007-04-16T09:37:16Z</dc:date>
    </item>
    <item>
      <title>Re: RAID 5</title>
      <link>https://community.hpe.com/t5/operating-system-microsoft/raid-5/m-p/3982183#M8000</link>
      <description>1- As your subject says, RAID 5 makes the 3 disks as one disk, using one of the disks as parity, so if one disk fails, data is not lost.&lt;BR /&gt;&lt;BR /&gt;You see two disks in windows because you have two partitions in the RAID 5 disk.&lt;BR /&gt;&lt;BR /&gt;2- You must alter the boot.ini file to include the /PAE boot option to be able to detect all memory.&lt;BR /&gt;&lt;BR /&gt;If you don't plan to install linux later, you missed the forum ;)</description>
      <pubDate>Mon, 16 Apr 2007 09:47:57 GMT</pubDate>
      <guid>https://community.hpe.com/t5/operating-system-microsoft/raid-5/m-p/3982183#M8000</guid>
      <dc:creator>Ivan Ferreira</dc:creator>
      <dc:date>2007-04-16T09:47:57Z</dc:date>
    </item>
    <item>
      <title>Re: RAID 5</title>
      <link>https://community.hpe.com/t5/operating-system-microsoft/raid-5/m-p/3982184#M8001</link>
      <description>woo, I would never say raid 5 uses one disk for parity. the parity is distributed across the disks. If only the one disk had all the parity data you would be up a creek if you lost just that disk.</description>
      <pubDate>Mon, 16 Apr 2007 10:43:53 GMT</pubDate>
      <guid>https://community.hpe.com/t5/operating-system-microsoft/raid-5/m-p/3982184#M8001</guid>
      <dc:creator>Court Campbell</dc:creator>
      <dc:date>2007-04-16T10:43:53Z</dc:date>
    </item>
    <item>
      <title>Re: RAID 5</title>
      <link>https://community.hpe.com/t5/operating-system-microsoft/raid-5/m-p/3982185#M8002</link>
      <description>&amp;gt; If only the one disk had all the parity data you would be up a creek if you lost just that disk.&lt;BR /&gt;&lt;BR /&gt;Hm. I disagee, because you still have all data on the remaining data disk drives. You are now running a RAID-0 set. Of course, it cannot withstand the loss of one more disk drive, but RAID-5 can't do that either.&lt;BR /&gt;&lt;BR /&gt;What Ivan has described (multiple data disk drives with all parity stored on one disk drive) is called RAID-4. The problem with this is that it is not good for a large number of writes, because the parity disk drive is always being hit.&lt;BR /&gt;&lt;BR /&gt;RAID-5 works around this by distributing the parity data across all disk drives in the RAID set.</description>
      <pubDate>Mon, 16 Apr 2007 11:48:01 GMT</pubDate>
      <guid>https://community.hpe.com/t5/operating-system-microsoft/raid-5/m-p/3982185#M8002</guid>
      <dc:creator>Uwe Zessin</dc:creator>
      <dc:date>2007-04-16T11:48:01Z</dc:date>
    </item>
    <item>
      <title>Re: RAID 5</title>
      <link>https://community.hpe.com/t5/operating-system-microsoft/raid-5/m-p/3982186#M8003</link>
      <description>&amp;gt;&amp;gt;&amp;gt;  1- As your subject says, RAID 5 makes the 3 disks as one disk, using one of the disks as parity, so if one disk fails, data is not lost.&lt;BR /&gt;&lt;BR /&gt;This was a simple explanation. If you want a more "strict" definition, consider "the space of one disk" for parity. Most people know that the RAID 5 parity is distributed.&lt;BR /&gt;&lt;BR /&gt;And for strict definition, it's not a RAID 4, maybe a RAID 3.</description>
      <pubDate>Mon, 16 Apr 2007 13:00:14 GMT</pubDate>
      <guid>https://community.hpe.com/t5/operating-system-microsoft/raid-5/m-p/3982186#M8003</guid>
      <dc:creator>Ivan Ferreira</dc:creator>
      <dc:date>2007-04-16T13:00:14Z</dc:date>
    </item>
    <item>
      <title>Re: RAID 5</title>
      <link>https://community.hpe.com/t5/operating-system-microsoft/raid-5/m-p/3982187#M8004</link>
      <description>Uwe, I agree. I wasn't thinking.&lt;BR /&gt;&lt;BR /&gt;Ivan, not trying to be picky, just wanted Abdul to have a more accurate description of raid5.</description>
      <pubDate>Mon, 16 Apr 2007 14:23:31 GMT</pubDate>
      <guid>https://community.hpe.com/t5/operating-system-microsoft/raid-5/m-p/3982187#M8004</guid>
      <dc:creator>Court Campbell</dc:creator>
      <dc:date>2007-04-16T14:23:31Z</dc:date>
    </item>
    <item>
      <title>Re: RAID 5</title>
      <link>https://community.hpe.com/t5/operating-system-microsoft/raid-5/m-p/3982188#M8005</link>
      <description>&amp;gt; it's not a RAID 4, maybe a RAID 3.&lt;BR /&gt;&lt;BR /&gt;Both, RAID-3 and RAID-4 use a dedicated parity disk drive, but RAID-3 uses a MUCH smaller chunk size than RAID-4 and RAID-5.</description>
      <pubDate>Mon, 16 Apr 2007 23:47:12 GMT</pubDate>
      <guid>https://community.hpe.com/t5/operating-system-microsoft/raid-5/m-p/3982188#M8005</guid>
      <dc:creator>Uwe Zessin</dc:creator>
      <dc:date>2007-04-16T23:47:12Z</dc:date>
    </item>
    <item>
      <title>Re: RAID 5</title>
      <link>https://community.hpe.com/t5/operating-system-microsoft/raid-5/m-p/3982189#M8006</link>
      <description>Thanks guys for your reply, but i still need a small help from you regarding the RAM issue.&lt;BR /&gt;Ivan and all, would you explain more on how to do it.&lt;BR /&gt;&lt;BR /&gt;Regards,</description>
      <pubDate>Tue, 17 Apr 2007 01:25:41 GMT</pubDate>
      <guid>https://community.hpe.com/t5/operating-system-microsoft/raid-5/m-p/3982189#M8006</guid>
      <dc:creator>Abdul R. Arab</dc:creator>
      <dc:date>2007-04-17T01:25:41Z</dc:date>
    </item>
    <item>
      <title>Re: RAID 5</title>
      <link>https://community.hpe.com/t5/operating-system-microsoft/raid-5/m-p/3982190#M8007</link>
      <description>Here is a thread where explains how to do it:&lt;BR /&gt;&lt;BR /&gt;&lt;A href="http://forums1.itrc.hp.com/service/forums/questionanswer.do?threadId=1009988" target="_blank"&gt;http://forums1.itrc.hp.com/service/forums/questionanswer.do?threadId=1009988&lt;/A&gt;&lt;BR /&gt;&lt;BR /&gt;Cheers.</description>
      <pubDate>Tue, 17 Apr 2007 08:27:46 GMT</pubDate>
      <guid>https://community.hpe.com/t5/operating-system-microsoft/raid-5/m-p/3982190#M8007</guid>
      <dc:creator>Ivan Ferreira</dc:creator>
      <dc:date>2007-04-17T08:27:46Z</dc:date>
    </item>
    <item>
      <title>Re: RAID 5</title>
      <link>https://community.hpe.com/t5/operating-system-microsoft/raid-5/m-p/3982191#M8008</link>
      <description>Ivan i would rate your reply 100 instead of  10:) &lt;BR /&gt;Thanks alot you bailed me out of a dilemma :)</description>
      <pubDate>Tue, 17 Apr 2007 08:52:59 GMT</pubDate>
      <guid>https://community.hpe.com/t5/operating-system-microsoft/raid-5/m-p/3982191#M8008</guid>
      <dc:creator>Abdul R. Arab</dc:creator>
      <dc:date>2007-04-17T08:52:59Z</dc:date>
    </item>
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