topic Re: counting sub-directories in Operating System - HP-UX

counting sub-directories

Gord Moore — Mon, 09 Feb 2004 12:23:03 GMT

On my 11i system, the automated process gets the error "Too many links" when trying to make a new directory (new log file directory every day, and several at the same time -- stupid application!)

Anyway, searching here I found that PHKL_28185 has removed vx_maxlink as a configurable parameter and set it to 65534. That should be enough, but I need to see how many directory links there are. I tried this but I am not sure I am getting the right number.

ls -R | grep "./" | wc -l

I am counting the number of times ./ appears which seems to be the start of a subdirectory.

Is there a better way?

Re: counting sub-directories

Jeroen Peereboom — Mon, 09 Feb 2004 12:27:05 GMT

Gord,

try
find . -type d | wc -l

(-type d: only directories).
If the count is approx the same as the ls -R, than it's OK?!

JP

Re: counting sub-directories

Steven E. Protter — Mon, 09 Feb 2004 12:27:41 GMT

I kind of like our way.

Its not very processor intensive.

numsub=$(ls -R grep "./" |wc -l)
export numsub

Now I know the number of subbies.

SEP

Re: counting sub-directories

Gord Moore — Mon, 09 Feb 2004 12:37:35 GMT

Slight difference in the counts, but either way tells me there are lots of sub-dirs out there.

> find . -type d | wc -l
31496
> ls -R | grep "./" | wc -l
31756

Thanks.

Re: counting sub-directories

H.Merijn Brand (procura — Mon, 09 Feb 2004 12:38:14 GMT

find should - in general - be the fastest, but they won't always give the same result.

sh-2.05b$ time perl -lMFile::Find -e'END{print$n}find(sub{-d&&$n++},".")'
19

real 0m0.109s
user 0m0.110s
sys 0m0.000s
sh-2.05b$ time find . -type d | wc -l
19

real 0m0.018s
user 0m0.010s
sys 0m0.010s
sh-2.05b$ time ls -R | grep "./" | wc -l
18

real 0m0.042s
user 0m0.020s
sys 0m0.020s
sh-2.05b$
timex

Enjoy, Have FUN! H.Merijn