topic Re: Simple 'find' command question in Operating System - HP-UX

Simple 'find' command question

Darrell Tyler_1 — Thu, 27 May 2004 10:09:35 GMT

Hello,
Is there a way of issuing the 'find' command to poll for â file ownerâ ? I have tried the below command with no luck

# find /home -user *ftp*
find: missing conjun

Re: Simple 'find' command question

RAC_1 — Thu, 27 May 2004 10:11:16 GMT

I think it has to be
find /home -user ftp

Anil

Re: Simple 'find' command question

Mark Grant — Thu, 27 May 2004 10:12:25 GMT

You can't use the '*' around the user name.

It would need to be "find /home -user ftp".

Re: Simple 'find' command question

TC ITEMS Unix Admin — Thu, 27 May 2004 10:13:58 GMT

you should not have the * around the username. The shell will interpret the * as a wildcard before executing the find command. so what you want is:

find /home -user ftp -type f -exec ls -l {} \;

Re: Simple 'find' command question

Anupam Anshu_1 — Thu, 27 May 2004 10:22:04 GMT

With -user option of commands you can give only +/- i.e.

find /home -user +101
find /home -user -101
find /home -user 101

find doesn't allow regular expressions for option to -user.
Anshu

Re: Simple 'find' command question

Geoff Wild — Thu, 27 May 2004 10:27:51 GMT

Yes - can not have *'s

-user uname True if the file belongs to the user uname.
If uname is numeric and does not appear as a
login name in the /etc/passwd file, it is
taken as a user ID. The uname operand can be
preceded by a + or - to modify the comparison
of the primaries. If the argument n
represents a decimal integer; +n means more
than n, -n means less than n, and n means
exactly n.

find /home -user ftp

Find only user with uis 21100
or find /home -user 21100

Find all users greater then uid 21099
or find /home -user +21099

Rgds...Geoff

Re: Simple 'find' command question

Robert-Jan Goossens — Thu, 27 May 2004 10:30:40 GMT

Anshu,

That is not right,

# cd /home
# find . -user gorj -type f -exec ll {} \;
-rwxr-xr-x 1 gorj users 65 Apr 20 13:03 .history
-rwxr-x--- 1 gorj users 341 Jun 13 2000 .login
-rw------- 1 gorj users 19124 Mar 25 10:51 .lsof
-rwxr-x--- 1 gorj users 1768 May 17 09:46 .profile

regards,
Robert-Jan

Re: Simple 'find' command question

Mel Burslan — Thu, 27 May 2004 10:32:42 GMT

if what you are doing is to find files owned by users who has the word ftp as a part of their username, you can do this

for username in `cat /etc/passwd | cut -d: -f1 | grep ftp`
do
find /home -user $username
done

Hope this helps

Re: Simple 'find' command question

Jose Mosquera — Thu, 27 May 2004 10:39:10 GMT

Hi,

Try the following lines:

USERS=`cat /etc/passwd|awk -F":" '{ print $1 }'|grep ftp`
for USER in $USERS
do
find /home -user $USER
done

If you need more information about found files replace previously "find" sintax by this:
find /home -user $USER -exec ll {} \;

BR.

Re: Simple 'find' command question

Darrell Tyler_1 — Thu, 27 May 2004 11:12:27 GMT

Hello again,
I want to thank you all for the information and perspective you have afforded me. I think of all, Mel Burslan is the closest to what Iâ m looking for - files that have ftp as a part of their owner

Re: Simple 'find' command question

iminus — Thu, 27 May 2004 17:59:17 GMT

Try find /home -user ""

you can specify wild card * for searching in the quotes.

Re: Simple 'find' command question

Dani Seely — Thu, 27 May 2004 20:13:18 GMT

Hey Darrell,
Based on your example you used in your question, Iminus was closest to your answer.

If you are looking for any user with ftp in the name (i.e. tftpuser) you would need to enclose the ftp in quotes with an asterisk before and after ...
# find /home -user "*ftp*"

If you are looking for a user with ftp in the name then you don't need quotes, you would use:
# find /home -user *ftp

Same for the reverse ... ftp, you would use:
# find /home -user ftp*

Your example shows two asterisks, so you would use the first example I show above.

Good luck!

Re: Simple 'find' command question

Darrell Tyler_1 — Fri, 28 May 2004 12:05:36 GMT

Thank you once again!