topic Re: decimals in shell script in Operating System - HP-UX

decimals in shell script

Tony LeBlanc — Tue, 20 Mar 2001 14:30:49 GMT

Would someone know how to remove the decimal from a decimal number?

ex)

var=5.6
echo $var (only want 5 to show)

Thanks,
Tony

Re: decimals in shell script

James R. Ferguson — Tue, 20 Mar 2001 14:52:23 GMT

Hi Tony:

One way is to use 'awk' with the "." as the field delimiter:

# V=5.6
# echo $V|awk -F. '{print $1}'

Regards!

...JRF...

Re: decimals in shell script

Curtis Larson — Tue, 20 Mar 2001 14:52:53 GMT

#!/usr/bin/ksh

integer i

var=5.6
i=$var
echo $i

Re: decimals in shell script

Danny Engelbarts — Tue, 20 Mar 2001 14:55:57 GMT

Tony,

With printf;

printf "%5.0f" $var

Greetz, Danny

Re: decimals in shell script

Andreas Voss — Tue, 20 Mar 2001 14:57:08 GMT

Hi,

just another way:

val=5.6
echo ${val%.*}

Regards

Re: decimals in shell script

John Palmer — Tue, 20 Mar 2001 15:00:42 GMT

The Korn or Posix shell's integer arithmetic facility is probably the most elegant solution.

Provided the value supplied is a valid number
(the shell will print a failure message to standard error if it isn't) then

let VAR=
print ${VAR}

will do the trick. The let command implies 'integer VAR' which is an alias to 'typeset -i VAR'

Regards,
John

Re: decimals in shell script

James R. Ferguson — Tue, 20 Mar 2001 15:07:11 GMT

Tony:

...and here's yet another:

# V=5.6
# echo "$V / 1"|bc

...JRF...

Re: decimals in shell script

Curtis Larson — Tue, 20 Mar 2001 15:08:54 GMT

if you use a more intelligent shell:

#!/usr/dt/bin/dtksh

var=5.6
print $(( var=int($var) ))

Re: decimals in shell script

Brian Markus — Tue, 20 Mar 2001 20:25:18 GMT

Well, Since people were posting some of the alternate ways of doing this. I decided to have some fun. I wrote this one out of pure boredom.

#!/bin/sh
#----------------------------------------------------------
# Script Written by: Brian Markus - bmarkus@rcoe.k12.ca.us
# Reason - pure boredom, and to help a fellow hpux'er
# This script will take any size decimal
# number assign the left side of the
# decimal to a variable named predec,
# then assign the right side of the decimal
# to a variable named postdec
#----------------------------------------------------------
# Set your variable with the decimal
# assign the the decimal number to decnum
decnum=549890.398

#display your variable before altering it
echo "pre number = $decnum"

#get the length of the variable
varlen=`expr length $decnum`

#find the position that the decimal is in
decpos=`expr index $decnum \.`

#set the end point for the left side of the decimal
let decpos=decpos-1

#assign the left side of the decimal to predec
predec=`expr substr $decnum 1 $decpos`

#set the beginning point on the right side of the decimal
let decpos=decpos+2

#assign the right side of the decimal to postdec
postdec=`expr substr $decnum $decpos $varlen`

#put the left and right side together with out the decimal
newnumber=${predec}${postdec}

#display the new built number
echo "post number = $newnumber"

hope this helps

Brian.

Re: decimals in shell script

Brian Markus — Tue, 20 Mar 2001 20:31:19 GMT

If you want to truncate the numbers after the decimal, you could just use the $predec var. and not process the rest. I got carried away. It's always best to follow the KISS rule. Everyone's posted a good solution. This method is a bit more advanced and cumbersome, but it's easy to follow.