topic Re: Question regarding cat...... in Operating System - HP-UX

Question regarding cat......

Joe Profaizer — Wed, 29 Jun 2005 15:46:53 GMT

I need to build the command: cat SanNon1MAR2005.txt SanNon2MAR2005.txt > SanNonMAR2005
when given a variable containing "SanNonMAR2005". And that's all we have to work with.

I need to split the contents of the variable into 2 pieces (SanNon) and (MAR2005) and insert a "1" and a "2" where necessary to build the stmt above.

If InputFile is my variable then 'echo $Inputfile | cut -c1-6' would give me SanNon. That's about as far as I've gotten....

Re: Question regarding cat......

A. Clay Stephenson — Wed, 29 Jun 2005 16:00:49 GMT

There are many ways to do this and if you look at an earlier patterm matching thread today you would get some good Perl ideas but to fix your approach:

PT1=$(echo "${Inputfile}" | cut -c1-6)
PT2=$(echo "${Inputfile}" | cut -c7-)

V1="${PT1}1${PT2}"
echo "V1 = ${V1}"
V2="${PT1}2${PT2}"
echo "V2 = ${V2}"

Re: Question regarding cat......

RAC_1 — Wed, 29 Jun 2005 16:01:07 GMT

var='SanNonMAR2005'
echo ${var#SanNon}
echo ${var%MAR*}

Anil

Re: Question regarding cat......

Sandman! — Wed, 29 Jun 2005 16:02:10 GMT

Joe,

Here's what you are looking for:
=============================================
Inputfile=SanNonMAR2005

echo $Inputfile | awk -F"M" 'BEGIN{OFS="M"} {print $1"1",$2}'
=============================================

the above code will give you "SanNon1MAR2005.txt". Replace the "1" in the awk command with the appropriate number (say 2) to build your cat command.

hope this helps!

Re: Question regarding cat......

A. Clay Stephenson — Wed, 29 Jun 2005 17:09:32 GMT

As I mentionioned earlier Perl is really the way to go for pattern matching.

Try this:
-----------------------------------
#!/usr/bin/sh

typeset -i STAT=1
typeset FNAME=''
typeset PT1=''
typeset MON=''
typeset YR=''
while [[ ${STAT} -ne 0 ]]
do
echo "Enter Filename: \c"
read FNAME
perl -e 'if ($ARGV[0] =~ /(.+)(JAN|FEB|MAR|APR|MAY|JUN|JUL|AUG|SEP|OCT|NOV|DEC)(\d{4})$/ ) { printf ("%s\t%s\t%s\n",$1,$2,$3); exit(0); } else { exit(1); }' "${FNAME}" | read PT1 MON YR
STAT=${?}
if [[ ${STAT} -ne 0 ]]
then
echo "Bad Format: FnameMONYYYY" >&2
fi
done
typeset CMD="cat ${PT1}1${MON}${YR}.txt ${PT1}2${MON}${YR}.txt > \
${PT1}${MON}${YR}"
echo "Cmd = \"${CMD}\""
exit ${STAT}
---------------------------------------

Note: The perl command including the read PT1 MON YR is all one line. The power of this approach is that it actually checks your filename for valid composition (valid monthname, 4 digit year). I've looked this over carefully and it should work. so that all you need to do is ${CMD} to actually exucute the built-up string.

Re: Question regarding cat......

Amit Agarwal_1 — Wed, 29 Jun 2005 23:49:01 GMT

You can use awk for this.

echo $InputFile | awk '{ printf("%s1%s2", substr($0, 1, 6), substr($0, 7));}'
-Amit

Re: Question regarding cat......

Sandman! — Thu, 30 Jun 2005 02:49:12 GMT

The "cat" command can be constructed with the awk excerpt given below:

==============================================================
# export InputFile="SanNonMAR2005"

# echo $Inputfile | awk -F"M" '{system("cat "$1"1M"$2".txt "$1"2M"$2".txt > "$0)}'
==============================================================

This will execute the code you want, i.e.

# cat SanNon1MAR2005.txt SanNon2MAR2005.txt > SanNonMAR2005

cheers!