topic Re: Doubt in crontab in Operating System - HP-UX

Doubt in crontab

Amadeus_1 — Mon, 23 Apr 2007 20:20:12 GMT

Hi,

i want to schedule the cron job in crontab on 2nd sunday of every month.

Is it possible?if so how to do it..

help apperciated .

Re: Doubt in crontab

A. Clay Stephenson — Mon, 23 Apr 2007 20:27:41 GMT

Not directly with cron, however you can run a script every Sunday and then let the script decide if it is the 2nd Sunday and take action or simply exit if not. The attached script, caljd.sh, will make this easy. I'll assume that you install it in /usr/local/bin. You script invoked by cron each Sunday should look very much like this:

------------------------------------------
#!/usr/bin/sh

typeset -i STAT=0

export PATH=${PATH}:/usr/local/bin

if [[ $(caljd.sh -N) -eq 2 ]]
then
echo "2nd Sunday; do your thing."
STAT=${?}
fi
exit ${STAT}
--------------------------------------------
Here's the caljd.sh attachment; invoke it as caljd.sh -u for full usage and many examples.

Re: Question on crontab

Dennis Handly — Sun, 18 Sep 2011 22:14:04 GMT

>Clay: you can run a script every Sunday and then let the script decide if it is the 2nd Sunday

You might want to reverse that and run it for every second week and then have the script test for Sunday. (Even though it fires off 7 days a month instead of 4 or 5, the scripting is easier.)

# The test for Sun is in the script.
00 05 08-14 * * gen_monthly_status

WD=$(date +"%a")
if [ $WD != "Sun" ]; then
exit
fi

If you are worried about locales, you may want to use "%u" and check for 7.

Re: Doubt in crontab

SANTOSH S. MHASKAR — Tue, 24 Apr 2007 00:47:30 GMT

Hi,

By using cron it is possible to schedule jobs
on all Sundays/Weekdays, for schjeduling on Sundays

If u want to schedule a job on every 2nd Sunday,
u schedule the job to run on all sundays and
check in the job itself if it is 2nd sunday or not.

eg.

ur cronfile may look like this.
--------------------------
0 0 20 * * 0 /
--------------------------

Add code to check occurance of Sunday in job.sh

job.sh
----------
#! /usr/bin/ksh

Day=`date +'%d'`
Week=`echo "scale=0;($Day + 6) / 7"|bc -l`

if [ $Week -eq 2 ]
then
fi