topic Re: listing files in Operating System - HP-UX

listing files

himacs — Sun, 29 Nov 2009 09:07:23 GMT

Hi admin,

My directory contains lots of files including files appended with date.I want to list files with no date appended.For example i want to list only test.txt not text.txt.11112009

Please suggest

regards
himacs

Re: listing files

R.K. # — Sun, 29 Nov 2009 09:23:33 GMT

Hi Himacs,

If all files in that directory contains 2009 then you can try this:

# ll | grep -v 2009*

Let me know if you have any exceptions.

Regds..

Re: listing files

chendan_1 — Sun, 29 Nov 2009 09:58:34 GMT

the "awk" command may help you.

Re: listing files

Wouter Jagers — Sun, 29 Nov 2009 13:30:44 GMT

This would remove any filenames from your listing which end on 6 or more digits

ls | perl -ne 'print if (!/\d{6}\d*$/)'

cheers

Re: listing files

Wouter Jagers — Sun, 29 Nov 2009 13:34:43 GMT

Sorry, seems I misread the question.

ls | sed 's/$.*$[0-9][0-9][0-9][0-9][0-9][0-9][0-9]*$/\1/'

would chop off the digits at the end, if 6 or more.

Re: listing files

Wouter Jagers — Sun, 29 Nov 2009 13:39:44 GMT

and this should do the same

perl -ne 's/(.*)[^0-9][0-9]{6}[0-9]*$/\1/; print;'

Re: listing files

Suraj K Sankari — Sun, 29 Nov 2009 15:05:36 GMT

Hi,

If its a single directiory then do "ls -lrt" and you will get the files with sorted date recent modify at last.

Suraj

Re: listing files

Patrick Wallek — Sun, 29 Nov 2009 17:07:37 GMT

What happens if you just do a

# ll *.txt

Re: listing files

James R. Ferguson — Sun, 29 Nov 2009 17:45:02 GMT

Hi HImacs:

Depending on your exact objectives, this might help:

# ls | grep -Ev "[0-9]{6}"

This will filter out files whose size is 6-digits in length if you do a long 'ls' listing, though (i.e. 'ls -l') so, this would correctly report files from that, too:

# ls -l | awk '$NF!~/[0-9]{6}/'

The assumption here is that a date that is part of the filename is exactly 6-digits long. If you always use the format of "MMDDYYYY" as you suggest in your example, a better expression might be:

ls -l | awk '$NF!~/[0-1][0-9][0-3][0-9][20][0-9][0-9]/'

In this case, the YYYY portion is assumed to be the year 2000 or later.

Regards!

...JRF...

Re: listing files

Dennis Handly — Mon, 30 Nov 2009 09:26:05 GMT

>I want to list only test.txt not text.txt.11112009

Then exclude that pattern:
ls !(*.[01][0-9][0-3][0-9][12][0-9][0-9][0-9])

>JRF: You probably didn't want [20]:
ll | awk '$NF !~ /[0-1][0-9][0-3][0-9]20[0-9][0-9]/'

Re: listing files

Arturo Galbiati — Mon, 30 Nov 2009 11:55:45 GMT

Hi himacs,
this should run (I'm not able to test it now):
ls -l !(*.*2009*)

this will excluse all file with 2009 in the suffix

HTH,
Art

Re: listing files

R.K. # — Mon, 30 Nov 2009 12:40:28 GMT

@Arturo

# ls -l !(*.*2009*) <<== Works good