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    <title>topic Re: system performance tuning in Operating System - HP-UX</title>
    <link>https://community.hpe.com/t5/operating-system-hp-ux/system-performance-tuning/m-p/4669525#M381650</link>
    <description>&lt;!--!*#--&gt; i want to add issue i faced &lt;BR /&gt;&lt;BR /&gt;the proplem i face i don't know the tool that tell me the accurate percentage of free memory &lt;BR /&gt;&lt;BR /&gt;1- glance tell you when press "m"&lt;BR /&gt; Phys Mem :   6.0gb    Free Mem:   4.5gb&lt;BR /&gt;2- glance tell you when press "w"&lt;BR /&gt;pseudo-swap                    memory       6.0gb      839mb &lt;BR /&gt;so from this statement we can say memory free is 6 - 839 say (1G) so the result is free memory 5 giga i don't know what is the true "4.5" or "5" &lt;BR /&gt;3- when use swapinfo -mat &lt;BR /&gt;&lt;BR /&gt;dev       12000       0   12000    0%       0       -    1  /dev/vg00/lvol2&lt;BR /&gt;reserve       -     503    -503&lt;BR /&gt;memory     6132     839    5293   14%&lt;BR /&gt;total     18132    1342   16790    7%       -       0    -&lt;BR /&gt;&lt;BR /&gt;so if we choose the memory + reserve we find the memory total 6 G and the user ( 503 + 839 ) = 1342 G and the free is ( 6 - 1342 ) so the result is 4802 G &lt;BR /&gt;so what is the true and acurate i am confused &lt;BR /&gt;</description>
    <pubDate>Tue, 03 Aug 2010 09:31:18 GMT</pubDate>
    <dc:creator>maximodb</dc:creator>
    <dc:date>2010-08-03T09:31:18Z</dc:date>
    <item>
      <title>system performance tuning</title>
      <link>https://community.hpe.com/t5/operating-system-hp-ux/system-performance-tuning/m-p/4669524#M381649</link>
      <description>hi every body i want to check system performance i usually use glance,top,sar and swapinfo but i confused in something so i need explanation about memi every body i want to check system performance i usually use glance,top,sar and swapinfo but i confused in something so i need explanation about memory issue &lt;BR /&gt;ory issue &lt;BR /&gt;&lt;BR /&gt;first i want check the memory usage i used glance i found this parameter so i need one shows me the differences between these parameters &lt;BR /&gt;&lt;BR /&gt;Total VM :   810mb   Sys Mem  :   747mb   User Mem:   533mb   Phys Mem :   6.0gb&lt;BR /&gt;Active VM:   560mb   Buf Cache:   275mb   Free Mem:   4.5gb   FileCache:      na&lt;BR /&gt;&lt;BR /&gt;&lt;BR /&gt;actually the physical memory 6 giga and the free 4.5 i understand that but need to understand what is the "Active VM:   560mb" and "Total VM :   810mb"&lt;BR /&gt;&lt;BR /&gt;and are these parameters belong to swap &lt;BR /&gt;&lt;BR /&gt;i run swapinfo -mta &lt;BR /&gt;             Mb      Mb      Mb   PCT  START/      Mb&lt;BR /&gt;TYPE      AVAIL    USED    FREE  USED   LIMIT RESERVE  PRI  NAME&lt;BR /&gt;dev       12000       0   12000    0%       0       -    1  /dev/vg00/lvol2&lt;BR /&gt;reserve       -     504    -504&lt;BR /&gt;memory     6132     839    5293   14%&lt;BR /&gt;total     18132    1343   16789    7%       -       0    -&lt;BR /&gt;&lt;BR /&gt;and  with glance i found swap space and swap pesudo &lt;BR /&gt;&lt;BR /&gt;             Mb      Mb      Mb   PCT  START/      Mb&lt;BR /&gt;TYPE      AVAIL    USED    FREE  USED   LIMIT RESERVE  PRI  NAME&lt;BR /&gt;dev       12000       0   12000    0%       0       -    1  /dev/vg00/lvol2&lt;BR /&gt;reserve       -     504    -504&lt;BR /&gt;memory     6132     839    5293   14%Swap Device                     Type        Avail       Used     Priority&lt;BR /&gt;--------------------------------------------------------------------------------&lt;BR /&gt;/dev/vg00/lvol2                device      11.7gb        0mb        1&lt;BR /&gt;pseudo-swap                    memory       6.0gb      839mb       -1&lt;BR /&gt;&lt;BR /&gt;total     18132    1343   16789    7%&lt;BR /&gt;&lt;BR /&gt;also i need to understand the "pseudo-swap" i found this statement in book but don't understand "if we have 1 giga memory and 1 giga swap we can run 1.75 g processes "       -       0    -&lt;BR /&gt;&lt;BR /&gt;also i need to understand the "pseudo-swap" i found this statement in book but don't understand "if we have 1 giga memory and 1 giga swap we can run 1.75 g processes " &lt;BR /&gt;&lt;BR /&gt;ok if we don't have the pseudo-swap how much processe in this situation 1 G ? i am asking &lt;BR /&gt;&lt;BR /&gt;&lt;BR /&gt;i hope any one help me to understand what is the prarmeters i must take care about .&lt;BR /&gt;many thanks .&lt;BR /&gt;</description>
      <pubDate>Tue, 03 Aug 2010 09:08:52 GMT</pubDate>
      <guid>https://community.hpe.com/t5/operating-system-hp-ux/system-performance-tuning/m-p/4669524#M381649</guid>
      <dc:creator>maximodb</dc:creator>
      <dc:date>2010-08-03T09:08:52Z</dc:date>
    </item>
    <item>
      <title>Re: system performance tuning</title>
      <link>https://community.hpe.com/t5/operating-system-hp-ux/system-performance-tuning/m-p/4669525#M381650</link>
      <description>&lt;!--!*#--&gt; i want to add issue i faced &lt;BR /&gt;&lt;BR /&gt;the proplem i face i don't know the tool that tell me the accurate percentage of free memory &lt;BR /&gt;&lt;BR /&gt;1- glance tell you when press "m"&lt;BR /&gt; Phys Mem :   6.0gb    Free Mem:   4.5gb&lt;BR /&gt;2- glance tell you when press "w"&lt;BR /&gt;pseudo-swap                    memory       6.0gb      839mb &lt;BR /&gt;so from this statement we can say memory free is 6 - 839 say (1G) so the result is free memory 5 giga i don't know what is the true "4.5" or "5" &lt;BR /&gt;3- when use swapinfo -mat &lt;BR /&gt;&lt;BR /&gt;dev       12000       0   12000    0%       0       -    1  /dev/vg00/lvol2&lt;BR /&gt;reserve       -     503    -503&lt;BR /&gt;memory     6132     839    5293   14%&lt;BR /&gt;total     18132    1342   16790    7%       -       0    -&lt;BR /&gt;&lt;BR /&gt;so if we choose the memory + reserve we find the memory total 6 G and the user ( 503 + 839 ) = 1342 G and the free is ( 6 - 1342 ) so the result is 4802 G &lt;BR /&gt;so what is the true and acurate i am confused &lt;BR /&gt;</description>
      <pubDate>Tue, 03 Aug 2010 09:31:18 GMT</pubDate>
      <guid>https://community.hpe.com/t5/operating-system-hp-ux/system-performance-tuning/m-p/4669525#M381650</guid>
      <dc:creator>maximodb</dc:creator>
      <dc:date>2010-08-03T09:31:18Z</dc:date>
    </item>
    <item>
      <title>Re: system performance tuning</title>
      <link>https://community.hpe.com/t5/operating-system-hp-ux/system-performance-tuning/m-p/4669526#M381651</link>
      <description>&amp;gt;I found this statement in book but don't understand "if we have 1 gig memory and 1 gig swap we can run 1.75 g processes"&lt;BR /&gt;&lt;BR /&gt;This is saying roughly 75% of memory can be used for pseudo-swap.  This may not be as simple for 11.31.&lt;BR /&gt;&lt;BR /&gt;&amp;gt;if we don't have the pseudo-swap how much processes in this situation 1 G?&lt;BR /&gt;&lt;BR /&gt;Yes but you don't want to do that.  And on 11.31 you can't.&lt;BR /&gt;&lt;BR /&gt;&amp;gt;so what is the true and accurate?&lt;BR /&gt;&lt;BR /&gt;Memory is also used for the kernel and the various disk/file caches.</description>
      <pubDate>Tue, 03 Aug 2010 12:32:25 GMT</pubDate>
      <guid>https://community.hpe.com/t5/operating-system-hp-ux/system-performance-tuning/m-p/4669526#M381651</guid>
      <dc:creator>Dennis Handly</dc:creator>
      <dc:date>2010-08-03T12:32:25Z</dc:date>
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