topic Re: lsof question in Operating System - HP-UX

lsof question

KPS — Fri, 01 Dec 2006 13:46:34 GMT

Hi

I have a need to use lsof to list open files for a specific user on my PA-RISC HP-UX 11.11 box.

I know if I use the fuser -u , that will show the open files that user has. Is there an option using lsof that gives you the actual amount of open files, because that's what I'm really after here.

Thanks,
KPS

Re: lsof question

Coolmar — Fri, 01 Dec 2006 13:50:52 GMT

lsof -u username will list the open files by that user...so if you do the following:

# lsof -u username |wc -l

That will give you the number of files opened by a particular user. Is that what you were looking for?

Re: lsof question

spex — Fri, 01 Dec 2006 13:52:04 GMT

Hi,

I think you meant 'lsof -u '. How about:

# lsof -u user1 | wc -l
for a count of user1's open files, and

# lsof | wc -l
for a system-wide count?

PCS

Re: lsof question

Sandman! — Fri, 01 Dec 2006 13:53:36 GMT

lsof takes the same option as fuser...

# lsof -u

Re: lsof question

Calandrello — Fri, 01 Dec 2006 13:56:22 GMT

friend
lsof |grep process name

Re: lsof question

KPS — Fri, 01 Dec 2006 13:57:54 GMT

Thanks everyone, piping this to a wc -l is the way to go. Thanks!

Re: lsof question

spex — Fri, 01 Dec 2006 14:00:02 GMT

fuser(1M):
-u Display the login user name in parentheses following each
process ID.

lsof(8):
-u s This option selects the listing of files for the user whose
login names or user ID numbers are in the comma-separated set
s - e.g., ``abe'', or ``548,root''. (There should be no
spaces in the set.)

Re: lsof question

Coolmar — Fri, 01 Dec 2006 14:11:43 GMT

Hi again,

Would you be so kind as to assign points to any that helped you.
:0)