topic Re: awk exit status in Operating System - HP-UX

Question with my awk section

Nadie_1 — Sat, 06 Oct 2012 00:26:13 GMT

Re: awk exit status

Dennis Handly — Sat, 23 Jun 2012 05:59:58 GMT

>all I need is either exit with 0 or non zero

END { if (FOUND != 1) {print " TSM Server = Not configured"; exit 1}}'

Re: awk exit status

Nadie_1 — Sat, 23 Jun 2012 11:39:48 GMT

Thanks for the suggesstion I have tried putting exit 1 where u suggessted and simulated the test again but script doesn't exist with non zero ??

Re: awk exit status

Dennis Handly — Sat, 23 Jun 2012 23:12:22 GMT

>but script doesn't exit with non zero?

Please paste your script so we can verify.

Re: awk exit status

Dennis Handly — Sun, 24 Jun 2012 06:42:09 GMT

> Above is the excerpt again, script itself works fine but doesn't exit with non zero code even when it is not registered.

I don't see my exit 1. I also don't see what is after awk.

/usr/bin/dsmc q se | awk '

/Server Name/ {

print " TSM Server = " $NF

FOUND=1

}

END {

if ( FOUND != 1 ) {

print " TSM Server = Not configured"

exit 1

}

if [ $? -ne 0 ]; then

exit 1

>Here is set -x for your perusal,

I see more than what you have in your script.

>exit status is 1 but it still goes ahead

You have to check for it. Or use "set -e".

Re: awk exit status

Nadie_1 — Sun, 24 Jun 2012 09:22:39 GMT

just to be precise with my code as per my previous post

some_command | awk '

/retrive_this_value/ { # if the value is none ie blank then exit the program but it doesn't exit and goes further, i don't know how to check the blank character here , i tried "" but obviously that didn't work for me

print " Virtual Memory = " $NF

FOUND=1

}

END {

if ( FOUND != 1 ) {

print " Virtual Memory = Not assigned--exiting program"

exit 2

}

if [ $? -ne 0 ]; then

exit 2

Re: awk exit status

Dennis Handly — Sun, 24 Jun 2012 20:52:04 GMT

>this is great help, I have got what I wanted.

If you are happy with the answers you were given, please click on the Kudos stars of each helpful post.

>lspath -l hdisk1 -s Enabled|grep fscsi|grep Enabled

You can optimize this to one grep:

lspath -l hdisk1 -s Enabled | grep "Enabled.*fscsi"

You can use "grep -c" to count and with a real shell should use $() vs ``:

DSKPATH=$(lspath -l $DISK -s Enabled | grep -c "Enabled.*fscsi") # this counts for 2 paths 1 per adapter

if [ $DSKPATH -lt 2 ]; then
echo "We don't have dual paths--exiting program now--"
exit 1

done

echo "We have dual paths for all disks"

>parameter # space - means there is no value assigned, and if it is true then simply exit the program)?

You could use:

if [ "$parameter" = "" ]; then

exit

>if the value is none ie blank then exit the program

If you want to check for an empty line, you can do:

/^#/ { exit 1}

Re: awk exit status

Nadie_1 — Sun, 24 Jun 2012 22:41:12 GMT

Thanks again , you have been great assist, I will test it and let you know if I have any hiccup but this should now resolve my hiccups :)

I've clicked on start to assign points but it only seems to add 1 point, is this maximum we can assign ?

once i have tested it i will close this thread by marking as "accept this as solution", i may have to ask some more question tho...

Regards

Re: awk exit status

Dennis Handly — Tue, 26 Jun 2012 02:28:47 GMT

>it only seems to add 1 point, is this maximum we can assign?

Yes, one per post.

>return 1 # not sure if this is where I need return or else where please correct

Yes, this will work for functions.

>if [ "$NF" = "" ]; then # How to check - :

Why bother? If you don't get a good exit status (0), you didn't find what you wanted.

If you do want to check, you can just check in awk for:

if ($NF == ":")

>return 0 # Please correct

SInce you aren't in an awk function, I would just use: exit 0

(In fact, awk will not let you use return unless you are in a function.)

># Main and do I need to execute my functions below?

Yes.

Re: awk exit status

Nadie_1 — Mon, 25 Jun 2012 21:57:16 GMT

Thanks again few more quest, my questions are next to # below

>return 1 # not sure if this is where I need return or else where please correct, i will test this today tho

Yes, this will work for functions.

>if [ "$NF" = "" ]; then # How to check - :

Why bother? If you don't get a good exit status (0), you didn't find what you wanted.

If you do want to check, you can just check in awk for:

if ($NF == ":") # So this check goes into the same place where I'm currently checking in my script

>return 0 # Please correct

SInce you aren't in an awk function, I would just use: exit 0

# Even if I'm not in awk i need to check return 1 or return 0, so i can make it uniform in the script

I guess i can replace return 1 with exit 1 which i originally had but where to check return 0 tho ?

># Main and do I need to execute my functions below?

# The way i have stuff in my main, is this the correct way of checking it or am i missing anything such as executing function etc ? please correct

Yes.

Re: awk exit status

Nadie_1 — Mon, 25 Jun 2012 22:01:03 GMT

sorry in one of my comment i meant to say i can replace exit 1 which i originally has in my code with return 1 but where to place return 0 tho ?

also pls correct me where to place return 1 and return 0 within awk function

then in my main if I need to execute my functions and then check status with if statement or the way i currently have in my script is OK ?

thanks for your help really this clarifies and helps me learn a lot

Re: awk exit status

Dennis Handly — Tue, 26 Jun 2012 02:48:34 GMT

># Even if I'm not in awk I need to check return 1 or return 0, so I can make it uniform in the script

>I guess I can replace return 1 with exit 1 which I originally had but where to check return 0 though?

If you are in an awk function, you can use return, to return a value. If you want to exit awk, you use exit.

In a shell function, you can use return, unless you want to exit the script.

>in one of my comment I meant to say I can replace exit 1 which I originally has in my code with return 1 but where to place return 0 though?

>pls correct me where to place return 1 and return 0 within awk function

You can only use exit, not return. In your case, you only need "exit 1", since "exit 0" is done on a normal exit.

>in my main if I need to execute my functions and then check status with if statement or the way I currently have in my script is OK?

It's ok if you use a Posix shell but not ksh88.

Otherwise you need:

if [ ! check_tsm_reg ]; then

Or you could use:

check_tsk_reg || status=1

Re: awk exit status

Nadie_1 — Tue, 26 Jun 2012 09:32:26 GMT

Thanks again, I will test it but if you can correct my script with your suggestion it will save me sometime as im doing many things, however im trying myself too to get this sorted ,

correct me if im wrong if I have exit 1 within awk function then it still exits the program rather then just exiting the awk function and continue with further instruction ie functions, i don't want to exit the program, i just want to capture return code 1 if error and then exit only after completing everything.

Also some_command display in the below format, if it is assigned it gives out some number and in this case i would like to return with rc 0

Online Virtual Memory : 3.00

If not assigned then it displays blank with ie (colon space -)

Variable Memory Capacity Weight : - (colon space -) i really need to capture (dash) i think since if the memory is available then it still prints colon (:)

i can't capture this with

if [ "$NF" == "-" ]; then

print "online memory is not configured, return 1"

return 1 #( at this stage if it type exit 1 it will exit the program which i don't want it)

can you please kindly correct my script that I posted with proper code so i can write more functions once i get the funtion both awk and shell functions right I can write several more functions. Please correct me if im not capturing the return code properly in my script, as i want to exit with either 0 or 1 , since i set my variable $success to 0....

Much appreciate your help

Re: awk exit status

Nadie_1 — Tue, 26 Jun 2012 09:33:18 GMT

by the way im using korn shell--thnx

Re: awk exit status

Dennis Handly — Tue, 26 Jun 2012 18:46:16 GMT

>if I have exit 1 within awk function then it still exits the program rather then just exiting the awk function

Right, it only exits awk.

>some_command display in the below format, if it is assigned it gives out some number and in this case I would like to return with rc 0
>Online Virtual Memory : 3.00

If you don't exit awk with "exit 1", it will exit with 0.

>Variable Memory Capacity Weight : - (colon space -) I really need to capture (dash)

In awk, you check with:

if ($NF == "-") {

print "online memory is not configured, return 1"

exit 1

}

Then in your script, you check for the bad awk exit status and return from that function.

Re: awk exit status

Nadie_1 — Tue, 26 Jun 2012 21:47:08 GMT

Can you please give me an example based on my script template how we capture the status , i tested it with exit 1 but it exits the program, and when i put return it complains that return should be within awk statement etc ? although i think i've put return 1 within awk......but anyway we can use exit 1 within awk since you recon it won't exit the program but appreciate if u can correct my code---thanks

Re: awk exit status

Dennis Handly — Tue, 26 Jun 2012 23:52:21 GMT

>Can you please give me an example based on my script template how we capture the status

I'm confused in your command output format. You mentioned:

>Online Virtual Memory : 3.00

>If not assigned then it displays blank with ie (colon space -)

>Variable Memory Capacity Weight : - (colon space -)

Does the one "Some_command" produce both outputs? Or there are two commands?

If you are only looking for "Variable Memory Capacity Weight" and need to check for "-", you can do:

Some_command | awk '

/Variable Memory Capacity Weight/ {

if ($NF == "-") next # see if better value later?

print "Memory = " $NF

FOUND=1

}

END {

if ( FOUND != 1 ) {

print " Virtual Memory is not OK"

exit 3

}

Re: awk exit status

Dennis Handly — Wed, 27 Jun 2012 16:31:41 GMT

>Online Virtual Memory : -

Then why are you looking for: "^Variable Memory Capacity Weight"

Re: awk exit status

Nadie_1 — Wed, 27 Jun 2012 22:09:49 GMT

sorry please ignore that, it should be read as "Virtual Online Memory"---my typo but in my actual script I have "Online Virtual Memory" instead of "Variable Capacity Weight"

problem is that script doesn't pick up (-) if it's not assigned and doesn't return NON zero return code ?

Re: awk exit status

Dennis Handly — Thu, 28 Jun 2012 05:03:08 GMT

>MEMORY=`some_command | grep "^Variable Memory Capacity Weight" | awk -F: '{print $2}'`

With -F:, you need to look for " -". But better to only use the default delimiter and remove the grep:

MEMORY=$(some_command | awk '/^Virtual Online Memory/ {print $NF}')

if [ "$MEMORY" != "-" -a "$MEMORY" != "" ]; then

echo "memory is configured"

else

print "memory is not configured"