topic Re: show files in a numeric range in Operating System - HP-UX

show files in a numeric range

support_billa — Wed, 12 Oct 2011 08:19:17 GMT

In directories I have hundreds of files like:

file0001.lst
file0002.lst
.
.
file0999.lst

i want to show files in a index range, example 30 til 60 .
input : index1
input : index2

my idea:

index1=$1
index2=$2

for file in $( ls file* )
do
index=$( basename ${file} .lst |sed "s|[a-z]||g" )
if [ ${index} -ge ${index1} -a ${index} -le ${index2} ]
then
ls -al $file
fi
done

Re: show files in a numeric range

Dennis Handly — Wed, 12 Oct 2011 10:53:37 GMT

If your format is always: file####.lst:

#!/usr/bin/ksh

# List files by range

if [ $# -ne 2 ]; then

echo "Usage: $0 first last" 1>&2

exit 1

typeset -i first=$1 second=$2

typeset -Z4 subnum

ls $(

while (( first <= second )); do

subnum=$first

echo "file$subnum.lst"

(( first += 1 ))

done) 2> /dev/null # ignore missing files

Re: show files in a numeric range

James R. Ferguson — Wed, 12 Oct 2011 10:52:36 GMT

Hi:

One way:

# perl -nle '($n)=m{\D+(\d+)};print if $n>=30 && $n<=60' file

...prints the names matching the criteria.

# perl -nle '($n)=m{\D+(\d+)};system(qq(ls -l $_)) if $n>=30 && $n<=60' file

...runs 'ls -l' on the matches.

Regards!

...JRF...

Re: show files in a numeric range

support_billa — Wed, 12 Oct 2011 12:20:07 GMT

hello,

both answers are perfect, shell i understand , perl it isn't so easy, but i can extend to use shell variables

perl -nle '($n)=m{\D+(\d+)};print if $n>=30 && $n<=60' file

my version for using in a shell, hope right ?

ls file* | \
first=98 second=105 perl -nle '($n)=m{\D+(\d+)};print if $n>=$ENV{"first"} && $n<=$ENV{"second"}'

regards

Re: show files in a numeric range

James R. Ferguson — Wed, 12 Oct 2011 12:32:46 GMT

Hi:

Your Perl modification was very well done! You can use barewords for the hash keys, though:

# ls file* | first=30 second=60 perl -nle '($n)=m{\D+(\d+)};print if $n>=$ENV{first} && $n<=$ENV{second}'

Regards!

...JRF...

Re: show files in a numeric range

support_billa — Fri, 14 Oct 2011 12:38:03 GMT

hello,

last question : when i try:

ls /tmp/20111010/file/file* | \
first=95 second=105 perl -nle '($n)=m{\D+(\d+)};print if $n>=$ENV{first} && $n<=$ENV{second}'

it shows nothing , print $n shows 20111010 .

ls /tmp/file/file* | \
first=95 second=105 perl -nle '($n)=m{\D+(\d+)};print if $n>=$ENV{first} && $n<=$ENV{second}'

is ok

regards

Re: show files in a numeric range

Dennis Handly — Fri, 14 Oct 2011 20:54:09 GMT

>when I try: ls /tmp/20111010/file/file* | \

>it shows nothing, print $n shows 20111010 .

Most likely it takes the first string of digits in your directory path and not the last in your filename?

Re: show files in a numeric range

James R. Ferguson — Fri, 14 Oct 2011 13:23:41 GMT

@support_billa wrote:

last question : when i try:

ls /tmp/20111010/file/file* | \
first=95 second=105 perl -nle '($n)=m{\D+(\d+)};print if $n>=$ENV{first} && $n<=$ENV{second}'

it shows nothing , print $n shows 20111010 .

Hi:

What's different about '/tmp/file/file' versus ' /tmp/20111010/file/file' ?

That is, show us what your 'ls' of each returns.

Regards!

...JRF...

Re: show files in a numeric range

H.Merijn Brand (procura — Sun, 16 Oct 2011 15:34:19 GMT

The number test should be done on the file name only if I read this thread correctly, not on the directory name. I'd use File::Find;

$ perl -MFile::Find -wle'find(sub{/(\d+)/&&$1>=95&&$1<=105&&print},"/tmp/20111010/file")'

but you might find that too terse