topic Re: Shell script in Operating System - HP-UX

Shell script

Leif Halvarsson_2 — Wed, 22 May 2002 07:14:07 GMT

Hi
I want to write a shell script that read a file and searches for lines beginning with # . I think I must use som kind of "pattern matching" (regular expression) but how do I get this work.

Re: Shell script

Sebastian Galeski_1 — Wed, 22 May 2002 07:17:24 GMT

cat /tmp/file.txt |grep "^#"

Re: Shell script

H.Merijn Brand (procura — Wed, 22 May 2002 07:18:19 GMT

1. grep '^#' file
2. perl -ne 'm/^#/&&print' file

Re: Shell script

Chris Wilshaw — Wed, 22 May 2002 07:18:23 GMT

Leif,

cat | grep ^#

should be what you need.

Re: Shell script

John Palmer — Wed, 22 May 2002 07:19:48 GMT

Hi,

grep will do this for you...

grep "^#"

will print all lines in which start with #.

If you want to process the lines in a script then you can write a shell script like this...

grep "^#" | {
while read LINE
do

done
}

Regards,
John

Re: Shell script

U.SivaKumar_2 — Wed, 22 May 2002 07:20:35 GMT

hi,
you can try
#grep "#" filename
if you want more logic you can use awk
#man awk

regards,
U.SivaKumar

Re: Shell script

John Carr_2 — Wed, 22 May 2002 07:31:49 GMT

Hi

these first options will return every line containing a # you need to test the first character of each line to get it right.

!#/usr/bin/ksh

for eachline in filename ;
do

if [[ eachline[0] -eq "#" ]] then
cat $eachline >> newfilename
fi

cant remember the syntax on the if statement can someone correct it please.

John.

Re: Shell script

John Carr_2 — Wed, 22 May 2002 07:37:47 GMT

please ignore my last comment of course the ^ will do it.

John.