topic Re: crontab filter in Operating System - HP-UX

crontab filter

wojtek75 — Tue, 26 Jan 2010 12:24:28 GMT

Hi,

my crontab is pretty long and complex and I would like to get non-commented lines which have day and month other than '*'. Any oneline script to perform it?

Re: crontab filter

Pete Randall — Tue, 26 Jan 2010 12:38:09 GMT

crontab -l |grep -v "#"

Pete

Re: crontab filter

wojtek75 — Tue, 26 Jan 2010 12:40:34 GMT

This only filters commented lines. What about picking the ones with day and month (3rd and 4th position of crontab entry) other than '*'?

Re: crontab filter

James R. Ferguson — Tue, 26 Jan 2010 12:43:13 GMT

Hi:

# crontab -l | perl -nale 'next if m{^\s*(#|$)};print if $F[2] !="*" and $F[3] !="*"'

Perl counts fields zero-relative, so the monthday and month are field two (2) and three (3).

Regards!

...JRF...

Re: crontab filter

James R. Ferguson — Tue, 26 Jan 2010 12:55:32 GMT

Hi (again):

ENOCOFFEE. The '!=' operator should have been 'ne' since we are comparing strings, not numbers. Hence:

# crontab -l | perl -wnale 'next if m{^\s*(#|$)};print if $F[2] ne "*" and $F[3] ne "*"'

Regards!

...JRF...

Re: crontab filter

Dennis Handly — Tue, 26 Jan 2010 13:17:04 GMT

You can also use awk:
crontab -l | awk '
substr($0, 1, 1) != "#" && NF >= 6 && $3 != "*" && $4 != "*" { print $0 }'