topic Re: How to get only the line indicated with "grep" ... in Operating System - HP-UX

How to get only the line indicated with "grep" ...

Manuales — Sat, 05 Feb 2011 06:27:23 GMT

Hi .. how can i get only "/usr" if there are directories containing the same word as follows?
i am in / ... into / there are the following directories and fiiles:
dr-xrwxrwx 5 bin bin /usr
drwxrwxrwx 5 bin bin /usr/user1
drwxrwxrwx 5 bin bin /usr/user2/b.txt
drwxrwxrwx 5 bin bin /usr/user3/a.txt
drwxrwxrwx 5 bin bin /usr/company1/
drwxrwxrwx 5 bin bin /usr/company1/user4
drwxrwxrwx 5 bin bin /usr/company1/user5

if i list /usr i get:
i am under /
ls -lrt | grep /usr .... i get all the lines that contains "/usr" ...
dr-xrwxrwx 5 bin bin /usr
drwxrwxrwx 5 bin bin /usr/user1
drwxrwxrwx 5 bin bin /usr/user2/b.txt
drwxrwxrwx 5 bin bin /usr/user3/a.txt
drwxrwxrwx 5 bin bin /usr/company1/
drwxrwxrwx 5 bin bin /usr/company1/user4
drwxrwxrwx 5 bin bin /usr/company1/user5

but i only want to get theline that only contains "/usr" as follows:
dr-xrwxrwx 5 bin bin /usr

and .. how about if i only want to get the line that says: /usr/company1/

ls -lrt | grep "/usr/company1/"
i only want to get:
drwxrwxrwx 5 bin bin /usr/company1/

and not all the lines below ...
drwxrwxrwx 5 bin bin /usr/company1/
drwxrwxrwx 5 bin bin /usr/company1/user4
drwxrwxrwx 5 bin bin /usr/company1/user5

please your help, thanks in advance.

Re: How to get only the line indicated with "grep" ...

Jose Mosquera — Sat, 05 Feb 2011 07:02:09 GMT

Hi,

For your case just try adding a blank space before last double quotes:
#ls -lrt | grep "/usr/company1/"

Rgds.

Re: How to get only the line indicated with "grep" ...

Dennis Handly — Sat, 05 Feb 2011 08:36:00 GMT

>how can I get only "/usr" if there are directories containing the same word as follows?

If you are looking for directories, you are going about this wrong. Use -d to only list the one directory: ll -d /usr /usr/company

But if you are practicing grep, you can look into -w or -x.

>Jose: For your case just try adding a blank space

That's not likely to work since there isn't a blank at the end of the line. You can use "$" as the end of line anchor instead:
ls -lrt | grep "/usr/company1/$"

Re: How to get only the line indicated with "grep" ...

Manuales — Sun, 06 Feb 2011 14:01:29 GMT

thanks for answering ..
never mind if it is a directory or file .. i mean, i am doing a loop and there i do not specify if it is a directory or not ... i only get the line with that word "/usr/company1/" the problem here is i get the 5 lines below when i use "grep", i forget tell you i have files under those directories ...

drwxrwxrwx 5 bin bin /usr/company1/
drwxrwxrwx 5 bin bin /usr/company1/user4
drwxrwxrwx 5 bin bin /usr/company1/user5
-rwxrwxrwx 5 bin bin /usr/company1/user5/file1
-rwxrwxrwx 5 bin bin /usr/company1/user5/file2

if i want to get the line with "/usr/company1/" i only want to get
drwxrwxrwx 5 bin bin /usr/company1/ and not the 5 lines .. how can i do that? what command or parameter can i use?

thanks in advance.

Re: How to get only the line indicated with "grep" ...

Dennis Handly — Sun, 06 Feb 2011 15:08:08 GMT

>never mind if it is a directory or file

That's important. If you don't want to expand directories, add that -d. (It doesn't change how non-directories are displayed.)

>how can I do that? what command or parameter can I use?

As I said above, adding -d would be easier. Or you can use "$" in the grep.

Re: How to get only the line indicated with "grep" ...

James R. Ferguson — Sun, 06 Feb 2011 15:48:56 GMT

Hi Manuales:

It is worth your noting that in addition to limiting matches to a string that is anchored (pinned) to the end of a line, you can also match a string only if it is anchored to the beginning of a line.

The '$' as the last character of a regular expression anchors the match to the end of a line.

The '^' as the first character of a regular expresson anchors the match to the beginning of a line.

Hence, as noted, to match '/usr/company/1' in your example, you could do:

# ... grep /usr/company/1$

If you had a 'ls -l' listing of both files and directories, you could match only files, for example, by doing:

# ls -l | grep ^-

...since files are listing on a line that begins with a '-'. Correspondingly, since symbolic links begin with 'l', this would find those:

# ls -l | grep ^l

For much much more about regular expressions, see the manpages for 'regexp(5)'.

Regards!

...JRF...

Re: How to get only the line indicated with "grep" ...

Peter Nikitka — Sun, 06 Feb 2011 18:05:11 GMT

Hi manuales,

long story short:
use
ls -lrt ... | grep '/usr/company1/$'

or if there may or may not a "/" at the end of your string
ls -lrt ... | grep '/usr/company1/*$'

mfG Peter

Re: How to get only the line indicated with "grep" ...

Manuales — Mon, 07 Feb 2011 23:06:27 GMT

Hi .. it works:
ls -lrt ... | grep '/usr/company1/*$'

thanks a lot.

Re: How to get only the line indicated with "grep" ...

Hakki Aydin Ucar — Tue, 08 Feb 2011 07:44:09 GMT

I am not sure it is working in that way ? OR I misunderstood totaly what you are looking for:
I mean:
# ls -lrt ... | grep '/usr/local/*$'
... not found
# ls -lrt | grep '/usr/local/*$'

but;

# cd
# ls -lR | grep "/usr/local/*"
./usr/local/include:
./usr/local/lib:
./usr/local/man:
./usr/local/man/de:

(you need to put company1 instead of local)

Re: How to get only the line indicated with "grep" ...

Hakki Aydin Ucar — Tue, 08 Feb 2011 08:13:24 GMT

# ls -ald /usr/company1

Re: How to get only the line indicated with "grep" ...

Hakki Aydin Ucar — Tue, 08 Feb 2011 12:27:08 GMT

On second though another approach might be ;
# ls -lR /usr/ |grep 'company1$'

Re: How to get only the line indicated with "grep" ...

Manuales — Fri, 11 Feb 2011 23:45:26 GMT

THANKS ALL FOR YOUR ANSWERS ...
One more question ...
how can i do this using a variable

valor="/home/direct1"
is this correct?
ls -lrt | grep "$valor$"

Re: How to get only the line indicated with "grep" ...

James R. Ferguson — Sat, 12 Feb 2011 00:13:11 GMT

Hi (again):

Better form, which avoids ambiguity, is to enclose the variable name with curly braces when performing parameter substitution:

# ls -lrt | grep "${valor}$"

The braces are required when parameter is followed by a letter, digit, or underscore that should not be interpreted as part of its name or when a named parameter is subscripted.

Good habits avoid surprises.

Regards!

...JRF...