topic Re: shell script - for loop statement in Operating System - HP-UX

shell script - for loop statement

amonamon — Wed, 10 Sep 2008 09:11:03 GMT

Hello

I have file:

0011
5566
1265
7889
7878

I should match pattern aabb so that output could be:

0011
5566

so far I did this:

set -A arr `echo "0:1:2:3:4:5:6:7:8:9" | nawk -F":" '{for(i=1;i<=NF;i++) print $i}'`
for num in ${arr[@]}
do

grep $num$num00 tmp
grep $num$num11 tmp
grep $num$num22 tmp
grep $num$num33 tmp
grep $num$num44 tmp
grep $num$num55 tmp
grep $num$num66 tmp
grep $num$num77 tmp
grep $num$num88 tmp
grep $num$num99 tmp

done

is there more effective way?

Re: shell script - for loop statement

amonamon — Wed, 10 Sep 2008 09:14:09 GMT

it could be nice if possible to have another for statement inside this one to loop from 0 - 9

Re: shell script - for loop statement

amonamon — Wed, 10 Sep 2008 09:25:43 GMT

again me
also I tryed this one..

#!/bin/ksh

k=0
l=0

while [ $k -lt 10 ]; do

while [ $l -lt 10 ]; do
grep $k$k$l$l tmp
l=`expr $l + 1`
done

k=`expr $k + 1`
done

again stupid result..

Re: shell script - for loop statement

Hemmetter — Wed, 10 Sep 2008 09:58:57 GMT

Hi

try this one:

$ grep "$[0-9]$\1$[0-9]$\2" file

and see regexp(5)

rgds
HGH

Re: shell script - for loop statement

Ollie Rowland — Wed, 10 Sep 2008 10:13:26 GMT

Hi,

Or you could use perl...

Create the script match.pl
#!/usr/bin/perl
while () {
($a, $b) = /(.).(.)./;
print $_ if ($_ =~ /$a$a$b$b/);
}

and put your numbers in match.txt

Execute with

cat match.txt | match.pl

Don't forget to make your match.pl executable!

Re: shell script - for loop statement

amonamon — Wed, 10 Sep 2008 10:40:19 GMT

no perl pleasee..

Hemmetter that was nice..but also with this grep numbers 7777 and 3333 and 1111 etc. are also colected..but they should not be taken.

Re: shell script - for loop statement

Ollie Rowland — Wed, 10 Sep 2008 10:46:09 GMT

#!/usr/contrib/bin/perl

while () {
($a, $b) = /(.).(.)./;
print $_ if ($_ =~ /$a$a$b$b/ and $a != $b);
}

<<< GRIN >>>

Re: shell script - for loop statement

Hemmetter — Wed, 10 Sep 2008 11:06:13 GMT

Hi again,

it is as easy as:

$ grep "$[0-9]$\1$[0-9]$\2" tmp | grep -v "$[0-9]$\1\1\1"

Rgds
HGH

Re: shell script - for loop statement

amonamon — Wed, 10 Sep 2008 11:18:36 GMT

nice..I would never come up with that easy line..

thanks

Re: shell script - for loop statement

James R. Ferguson — Wed, 10 Sep 2008 16:05:32 GMT

Hi Amonamon:

> no perl please...

Why? Perl runs on virtually any kind of platform you can find --- that "other" operating system, too.

A shell script can just as easily run a Perl snippet as it can a 'grep' process.

All that aside, here's a regular expression in Perl (using negative look-ahead) to do your job:

# X="0011\n5566\n1265\n7889\n7878" #...your data

# echo ${X} | perl -ne 'print if m{ ((^\d)\2) (?!\2) }x'
0011
5566

Regards!

...JRF...

Re: shell script - for loop statement

amonamon — Thu, 11 Sep 2008 06:58:28 GMT

well...:( no perl becouse I do not have experience with it..and I do not have it installed..

also haw to match numbers taht are incremented?

like

0123
5678
3456
4567
1111
0011
9999

result should be:

0123
5678
3456
4567

so far I tryed this: please do not laugh..:)

grep "$[0-9]$\(\1+1)\(\1+2)\(\1+3)" tmp

thanks.

Re: shell script - for loop statement

Ollie Rowland — Thu, 11 Sep 2008 07:18:53 GMT

Hi,

I know you don't want perl, but here goes anyway:

#!/usr/contrib/bin/perl

while () {
($a, $b, $c, $d) = /(.)(.)(.)(.)/;
print $_ if ($_ =~ /^$a$b$c$d$/ and $b == $a+1
and $c == $b+1
and $d == $c+1 );
}

Re: shell script - for loop statement

Hemmetter — Thu, 11 Sep 2008 07:33:19 GMT

hi,

since all ascending 4 digit sequences are:
"0123|1234|2345|3456|4567|5678|6789"

it ist a simple grep statement:
$ egrep "0123|1234|2345|3456|4567|5678|6789" tmp

rgds
HGH

Re: shell script - for loop statement

Ollie Rowland — Thu, 11 Sep 2008 07:38:26 GMT

Hi,

Thanks Hemmetter, I've also learned lots with this thread.

It's a shame I can't assign points to you for this......!