topic Re: how to substitute variable in awk. in Operating System - HP-UX

how to substitute variable in awk.

ankurp — Thu, 10 Feb 2005 04:14:38 GMT

Hi friends,

I want check if all my servers are up by this script, can any one help me with 2 issues

1) How to insert variable in awk (awk '$1 == "$a" { print $0 } ' /etc/hosts )

2) How to set timeout for ping ?

#!/bin/sh

for a in
` sed -n '/202/p' /usr/scripts/ping_server.sh | awk ' { print $1 } '`
do
echo pinging $a

flag=`ping $a -n 3`
echo $flag | grep -i '0% packet loss'
echo $?

if [ "$?" -eq 0 ]
then

h=`awk '$1 == "$a" { print $0 } ' /etc/hosts `
echo " $h Host Alive "

fi

done

Waitn for u r responce.

Rgds
Ankur

Re: how to substitute variable in awk.

Steve Lewis — Thu, 10 Feb 2005 04:32:12 GMT

man awk tells you to use -v parameter

awk -v myvar=$a '{print myvar}' filename

But
A far better method to check to see if your hosts are up is to use ruptime.

vi /etc/rc.config.d/netdaemons
set RWHOD=1
start rwhod

then, define host equivalence for your machines.
$ ruptime

It will run uptime on all your remote systems and list them all at once. It also shows the load on each machine.

Re: how to substitute variable in awk.

Laurent Menase — Thu, 10 Feb 2005 04:50:17 GMT

try awk '$1 == "'"$a"'" { print $0 } ' /etc/hosts `

Re: how to substitute variable in awk.

Steve Lewis — Thu, 10 Feb 2005 04:51:10 GMT

You can also use this:

export A=2
awk '{p=ENVIRON["A"];print p}'

2

Re: how to substitute variable in awk.

ankurp — Thu, 10 Feb 2005 06:49:27 GMT

thanks laurant and steve for ur quick responces.
Im happy.
For laurant : awk: Field $() is not correct.
The input line number is 1. The file is /etc/hosts.
The source line number is 1.

Steve's thing worked , but had to some tweakin.

Regards
Ankur

Re: how to substitute variable in awk.

ankurp — Thu, 10 Feb 2005 06:53:07 GMT

This is how we can address variable "a" in awk.
awk '$1 == ENVIRON["a"]
{ print $0 } ' /etc/hosts