topic How to parse out fields using awk? in Operating System - HP-UX

How to parse out fields using awk?

Gino Castoldi_2 — Mon, 14 Jun 2004 08:47:04 GMT

Hi,

I have a shell script that finds and lists the full path to a file. (The filename always changes) I need to parse out all fields including the forward slashes because I only need the filename at the end of the path.
ex. /var/opt/filename
What would be the best way to do this?

10 points ot any good answer.
TIA, Gino

Re: How to parse out fields using awk?

harry d brown jr — Mon, 14 Jun 2004 08:52:05 GMT

man basename

live free or die
harry

Re: How to parse out fields using awk?

Jose Mosquera — Mon, 14 Jun 2004 08:53:21 GMT

Hi,

Are you looking for the "basename" command?
#man basename

Rgds.

Re: How to parse out fields using awk?

Mark Grant — Mon, 14 Jun 2004 08:53:50 GMT

This is confusing to me.

Firstly "basename /var/opt/filename" will give you "filename". However, I don't understand why you would need to do this because presumably you already had the filename in order to find it.

Re: How to parse out fields using awk?

Gino Castoldi_2 — Mon, 14 Jun 2004 08:55:47 GMT

Hi,

Mark: I'm using the 'find' command to locate the file so it returns the fullpath.

All: The 'basename' command looks like the solution to me.

10 points to any good answer.
TIA, Gino

Re: How to parse out fields using awk?

harry d brown jr — Mon, 14 Jun 2004 08:58:00 GMT

Also dirname returns the directory:

# filevar=/var/adm/syslog/syslog.log
# basename $filevar
syslog.log
# dirname $filevar
/var/adm/syslog
#

live free or die
harry

Re: How to parse out fields using awk?

MarkSyder — Mon, 14 Jun 2004 09:02:33 GMT

If you're using find, how about:

find / -name filename -exec basename {} \;

Mark Syder (like the drink but spelt different)

Re: How to parse out fields using awk?

Victor Fridyev — Mon, 14 Jun 2004 09:08:13 GMT

Hi,

basename $FILE
and
dirname $FILE
are the best solution, but if you like awk:
PATH=$(echo $FILE|awk -F/ '{$NF="";print}' | sed 's? ?/?g'

HTH

Re: How to parse out fields using awk?

Fabio Ettore — Mon, 14 Jun 2004 09:08:46 GMT

Hi Gino,

sorry, but the find command doens't already show the fullpath?
For example:

filename under /pippo/pluto
# find / -name filename
/pippo/pluto/filename

It returns fullpath then I don't understand your problem.
Otherwise I hope that other ITRC guys will help you better than me.

Best regards,
Ettore

Re: How to parse out fields using awk?

Gino Castoldi_2 — Mon, 14 Jun 2004 09:12:43 GMT

Hi,

Fabio: When I run the find command while searching for a particular file it returns the full path with the file itself.
I just need the file name by itself, I want to remove the rest of the string (which includes the full path).

10 points to any good answer.
TIA, Gino

Re: How to parse out fields using awk?

Fabio Ettore — Mon, 14 Jun 2004 09:15:34 GMT

Ok, now I understand your problem.
I saw your first post but the second one diverted me:

***************
Mark: I'm using the 'find' command to locate the file so it returns the fullpath.
***************

No points for me....

Best regards,
Ettore

Re: How to parse out fields using awk?

Steve Post — Tue, 15 Jun 2004 07:31:53 GMT

Ok.....
find /mydir -print | xargs basename?
NO. THAT won't work.
How about...
find /mydir | awk -F/ '// {print $NF}'
Yep. That looks right. I saw the awk command in the forums above.

But if you are looking for the base name perhaps you are just looking for the file?
If that's the case....."I want to find a file that begins with "billy".
find /mydir -name "billy*" -print | awk -F/ '// {print $NF}'

In awk the -F/ is means separate the fields by the / character.
The $NF means the current number of fields on that line.
So print $NF means print the last field on the line.

Re: How to parse out fields using awk?

Bill Hassell — Tue, 15 Jun 2004 07:52:38 GMT

basename and dirname do a great job in parsing just the name and the path respectively. However, the shell already knows how to do this so you can bypass awk, sed and basename with something like this:

find /somewhere | while read
do
echo ${REPLY##*/}
done

Re: How to parse out fields using awk?

H.Merijn Brand (procura — Tue, 15 Jun 2004 08:11:25 GMT

# perl -MFile::Find -MCwd=abs_path 'find (sub { my $filename = $_ ; my $relative_name = $File::Find::name; my $fullname = abs_path ($_) }, @ARGV)' dir dir dir

Modify to your liking

Enjoy, Have FUN! H.Merijn

Re: How to parse out fields using awk?

Tom Maloy — Tue, 15 Jun 2004 08:50:12 GMT

If you are using ksh, you can use variable manipulation.

If the variable is stored in variable "fn", try this:

echo ${fn##*/}

and it should show you just the file name.

The "##" removes the large left pattern.
The "*/" is the pattern to be removed.

Tom

Re: How to parse out fields using awk?

Muthukumar_5 — Sat, 19 Jun 2004 04:32:00 GMT

Hai.

You can get the directory name and pathname of all regular files using,

#!/usr/bin/ksh

echo " DIR-NAME FILE-NAME"
find / -type f | while read file; do
echo "`dirname $file` `basename $file`"
done

For other files like character files,block devices change the -type X value from man find

Regards,
Muthukumar.