topic what does "!*" do in shell script? in Operating System - HP-UX

what does "!*" do in shell script?

Henry Chua — Tue, 07 Sep 2004 09:02:27 GMT

Recently I encounter a line in a shell program that I dun quite understand..
i.e. :
"'onintr -;T0 path $planpath \!*;T1 start \!* $t2;onintr "

T0, T1, and t2 all are assigned value in intial declaration..
what I am interested to know is what does these commands do and especially
what does the "!*" serve as.. ?

Re: what does "!*" do in shell script?

Manish Srivastava — Tue, 07 Sep 2004 09:12:20 GMT

Hi,

In bash it gives the arguments of the last executed command.

manish

Re: what does "!*" do in shell script?

Henry Chua — Tue, 07 Sep 2004 09:20:41 GMT

ic.. but how does it works?.. in this case.. or maybe an example to illustrate?...

thank you all for your advise!

Re: what does "!*" do in shell script?

Michael_356 — Tue, 07 Sep 2004 09:22:00 GMT

onintr : Controls the action of the shell on interrupts.
If - is specified, all interrupts are ignored.

The end of the line reset the interrupts-command

Regards

Michael

Re: what does "!*" do in shell script?

Rodney Hills — Tue, 07 Sep 2004 09:56:19 GMT

onintr is a "csh" internal command and !* returns the last commands arguments into the command string (like bash).

The code you have turns off interupts, runs the program specified by T0 passing parameter "path $planpath" followed by the arguments from the command line that launched the script, then the program specified by T1 is run passing argument "start" followed by the command line arguments again, followed by "$t2".
The onintr at the end resets the "on interupt flag".

HTH

-- Rod Hills

Re: what does "!*" do in shell script?

Henry Chua — Wed, 08 Sep 2004 03:26:25 GMT

SOLVED .THANKS!!