topic Re: Scripting Question in Operating System - HP-UX

Scripting Question

Craig Rants — Fri, 07 Dec 2001 15:06:33 GMT

I have to breakdown the contents of a field in the same manner each time I come upon this field. The format of the field is 123456789XX0000. I want to remove the first 9 numbers from the field so the result would be XX0000. I know how I would approach this for command line arguments with shift. And I know how I could do this by processing each field through a while or for statment. But this is quite a big file and I don't want this to run all weekend. So basically my question is, is there a way to format the field in a similar manner to the shift command.

All responses are appreciated.

Craig

Re: Scripting Question

James R. Ferguson — Fri, 07 Dec 2001 15:11:03 GMT

Hi Craig:

Try this:

# echo "123456789xxxx1234"|awk '{print substr($0,10,8)}'

Regards!

...JRF...

Re: Scripting Question

Craig Rants — Fri, 07 Dec 2001 15:13:46 GMT

Bingo!
Good to see the master at work.

Craig

Re: Scripting Question

Deshpande Prashant — Fri, 07 Dec 2001 15:25:45 GMT

HI
One more choise if you need fields from 10th position through last.

echo "1234567890xabcdef" |cut -c 10-

Thanks.
Prashant.

Re: Scripting Question

Darrell Allen — Fri, 07 Dec 2001 15:26:55 GMT

Hi Craig,

Here's another way:

echo "123456789xxxx1234"|cut -c10-

Darrell

Re: Scripting Question

Craig Rants — Fri, 07 Dec 2001 15:34:15 GMT

I had tried cut and I must have missed something in my syntax.

Now I know.

Craig

Re: Scripting Question

harry d brown jr — Fri, 07 Dec 2001 18:47:14 GMT

echo "123456789XX0000"|sed "s/^$[0-9]\{9\}$$.*$/\2/"

for xx0000

or echo "123456789XX0000"|sed "s/^$[0-9]\{9\}$$..$$.*$/\3/"

for 0000

live free or die
harry