topic Re: Awk syntax in Operating System - HP-UX

Awk syntax

Mike Gordon — Thu, 28 Sep 2000 12:24:49 GMT

I have a small script that is used to monitor and warn myself if certain filesystems exceed a set capacity ie more than 80% used etc.

This is currently done using the following syntax :

space=`bdf | awk '$6 == "/" {print $5}' | cut -f1 -d"%"`

I would like to amend the script so filesystems are picked up from a configuration file instead of being hardcoded. Intended syntax is something like :

for fs in `cat filesystems`
do
space=`bdf | awk '$6 == $fs {print $5}' | cut -f1 -d"%"`

etc

Appears that value for $fs is not being determined. Awk fails with :

awk: Field $() is not correct.
The input line number is 1.
The source line number is 1.

Any ideas much appreciated.

Mike

Re: Awk syntax

Andreas Voss — Thu, 28 Sep 2000 12:33:29 GMT

Hi,

within your awk $fs is not known because it's a shell variable.
To tell awk the variable $fs use:
space=`bdf | awk -v fs=$fs '$6 == $fs {print $5}' | cut -f1 -d"%"`

Regards

Andrew

Re: Awk syntax

James R. Ferguson — Thu, 28 Sep 2000 12:36:26 GMT

Mike:

Do this:

Make your /tmp/stuff file like this:

/tmp
/var
/home

Then:

for fs in `cat /tmp/stuff`
do
space=`bdf|awk -v fs=$fs '$6==fs {print $5}'|cut -f1 -d"%"`
done

...adding whatever you want in the do-loop.

...JRF...

Re: Awk syntax

Andreas Voss — Thu, 28 Sep 2000 12:37:17 GMT

Sorry, if you assign a variable with -v var=value the within awk you must not use the $ before that var:
space=`bdf | awk -v fs=$fs '$6 == fs {print $5}' | cut -f1 -d"%"`

Re: Awk syntax

James R. Ferguson — Thu, 28 Sep 2000 12:37:59 GMT

Re: Awk syntax

John Palmer — Thu, 28 Sep 2000 12:39:37 GMT

You could also use the fact that bdf will take a filesystem as an argument:-

for fs in $(do
space=$(bdf ${fs} | tail -1|awk '{print $5}')
space=${space%%\%}
etc etc
done

Re: Awk syntax

John Palmer — Thu, 28 Sep 2000 12:45:30 GMT

Or without using 'tail':-

for fs in $(do
space=$(bdf ${fs} | awk '{if ($1 ~ /\//) {print $5}}')
space=${space%%\%}
etc etc...
done

Re: Awk syntax

박수정 — Fri, 29 Sep 2000 03:36:12 GMT

Hi!

Use this script...

.....

current_mounted_fs=`bdf | grep "/" |
awk '{if (NF == 6) {print $6}};
(NF == 5) {print $5}'`

for fs in $current_mounted_fs
do
used_rate=`bdf $fs | grep $fs
| awk '{if (NF == 6) {print $5}};
(NF == 5) {print $4}'
| awk -F% '{print $1}'`
if [ $used_rate -gt 80 ] ; then
echo "Waring! $fs used $used_rate% ..."
fi
done

.....

Re: Awk syntax

Werner Vergauwen — Fri, 29 Sep 2000 05:50:26 GMT

Bear in mind though the "-v" parameter is an extension to the awk syntax, and might not work on all platforms.

So you could also use double quotes in stead of single, like so :
space=`bdf | awk "$6 == $fs {print $5}" | cut -f1 -d"%"`

cheers

Re: Awk syntax

Fred Martin_1 — Fri, 29 Sep 2000 14:33:40 GMT

Here's a fragment that I wrote for my own use. As written it alerts you when any file system is 90% or greater capacity:

if [ "`/usr/bin/bdf | grep dev | /usr/bin/awk '{print $5}' | /usr/bin/sed 's/\%//g' | /usr/bin/awk '
{if($0>=90){print "OVER"}}
'`" != "" ]
then
# here you can send email or whatever
fi

Re: Awk syntax

Fred Martin_1 — Fri, 29 Sep 2000 14:40:41 GMT

Sorry, a lot was lost in the translation in that last message. I have included the script as an attachment here.
Fred