topic Re: let under kornshell in Operating System - HP-UX

let under kornshell

Harris Chandra — Sun, 15 Oct 2000 06:51:23 GMT

Does anybody know why the command line herebelow sends a SIGERR under HPUX/9000 kornshell ?

let k=1-1

example:
--------
#!/bin/ksh
trap 'echo SIGERR detected $?' ERR
let k=2-1
let k=1-1
let k=1-2

Re: let under kornshell

RikTytgat — Sun, 15 Oct 2000 17:09:11 GMT

Hi,

Because (extract from linux ksh manpage):

let [expression ...]
Each expression is evaluated, see Arithmetic Expressions above. If all expressions are successfully evaluated, the exit status is 0 (1) if the last expression evaluated to non-zero (zero).

So, exit status is 1 when result is 0, and since 1-1 equals 0 ...

Hope this helps,
Rik.

Re: let under kornshell

Harris Chandra — Mon, 16 Oct 2000 17:24:33 GMT

I still don't understand why it should send a SIGERR. One minus one or two minus two is clearly zero without error, and no one makes any mistake.
Unix is very bizarre, no wonder why Windows NT with its Visual Basic is progressing.