topic Grep/Awk functionalty request in Operating System - HP-UX

Grep/Awk functionalty request

Dave Walley — Fri, 03 Nov 2000 11:51:09 GMT

Hi.

I am looking for your assistance once again.

This time I need to extract from a file the last field regardless of whether it is the fourth, fifth or sixth fields, for example

1679 <****** DWDW COPY VWC87.
1788 CR362 * HGHT HTYG COPY VW4B0.
1793 <** JHGF DERE HGFDE GGG COPY VW4C8.

in this example I would need VWC87., VW4B0. and VW4C8. returned.

Can anybody help please.

Thanking you.

Dave

Re: Grep/Awk functionalty request

Rainer_1 — Fri, 03 Nov 2000 11:57:07 GMT

here the solution:
awk '{print $NF}'

Re: Grep/Awk functionalty request

Andreas Voss — Fri, 03 Nov 2000 12:01:16 GMT

Hi,

simply use:
awk '{print $NF}' file

Regards

Re: Grep/Awk functionalty request

Andreas Voss — Fri, 03 Nov 2000 12:03:53 GMT

Hi,

simply use:
awk '{print $NF}' file

Regards

Re: Grep/Awk functionalty request

Stefan Schulz — Fri, 03 Nov 2000 12:09:04 GMT

Try awk '{print $NF}' yourfile. $NF is the last field of every line in yourfile. The whitspace is the default field seperator. If you want to use another field seperator use awk -F: .... (to use ':' as field seperator).

Hpe this helps.

Regards

Stefan

Re: Grep/Awk functionalty request

federico_3 — Fri, 03 Nov 2000 12:27:58 GMT

Try:

cat your_file | awk '{print $NF}'

federico

Re: Grep/Awk functionalty request

Ralph Grothe — Fri, 03 Nov 2000 13:31:14 GMT

Maybe a superfluous addition,

you can do integer arithmetic with the awk qualifiers like NR, NF.
Sometimes some output produces inconsistent (or rather unpredictable) numbers of fields, but you know that the wanted field is always say n-2

awk '{print $(NF-2)}' /your/file/to/parse