topic Re: Unix scripting Date formating in Operating System - HP-UX

Unix scripting Date formating

Edward_12 — Tue, 20 Aug 2002 15:31:07 GMT

Hi there, I need some help.
I want to get the seconds after midnight. in the format 'sssss. I have tried:

H=$(date +%H)
M=$(date +%M)

S=$(($H*60*60)+($M*60))

It gives seconds for an old time.

Thanks

Re: Unix scripting Date formating

Justo Exposito — Tue, 20 Aug 2002 15:44:28 GMT

Hi Edward,

Something like that?

integer sec=0
integer sec1=0
integer sec2=0
integer Hour=$(date +%R | cut -d":" -f1)
integer Minute=$(date +%R | cut -d":" -f2)
(( sec1 = $Hour * 60 * 60 ))
(( sec2 = $Minute * 60 ))
(( sec = $sec1 + $sec2 ))

echo $sec

Regards,

Justo.

Re: Unix scripting Date formating

harry d brown jr — Tue, 20 Aug 2002 15:45:57 GMT

S=$(($H * 3600 + $M * 60 ))

live free or die
harry

Re: Unix scripting Date formating

Dave Chamberlin — Tue, 20 Aug 2002 15:46:00 GMT

try this:
S = `exec $H \* 3600 + $M \* 60'
echo $S

Re: Unix scripting Date formating

James R. Ferguson — Tue, 20 Aug 2002 15:46:10 GMT

Hi:

Seconds are available:

S=S=$(date +%S)

Then:

# let X=$$H*3600$+$$M*60$+$S

Regards!

...JRF...

Re: Unix scripting Date formating

Dave Chamberlin — Tue, 20 Aug 2002 15:47:17 GMT

correction -
S = `exec $H \* 3600 + $M \* 60`

Re: Unix scripting Date formating

A. Clay Stephenson — Tue, 20 Aug 2002 15:47:34 GMT

Here is one simple solution. One thing to avoid is multiple date calls.

S=$(date '+%T' | awk -F: '{print ($1 * 3600) + ($2 * 60) + $3)')

Re: Unix scripting Date formating

Rodney Hills — Tue, 20 Aug 2002 15:49:15 GMT

Be sure you have balanced paraenthesis.

S=$((($H*60*60)+($M*60)))

The first $(( is for expressions calculation.
You need parenthesis to balance the formula.

-- Rod Hills