topic RE match pattern used in grep command in Operating System - HP-UX

RE match pattern used in grep command

Jdamian — Thu, 20 Nov 2003 05:52:57 GMT

Hi.

A script provided by my HP Account engineer requested me the system handle of my box. But the following error messages was repoted:

Unprintable character in 'MYSYSTEM-9000'.

I debbuged that script and found the lines that check my input:

if [ "`echo $user_info | grep '^[ !-~]*$'`" = "" ]
then
echo ""
echo "Unprintable character in '$user_info'."
continue
fi

The problem was the grep command. The following command line prints nothing:

echo hello | grep '^[ !-~]*$'

but the following alternate command line works fine:

echo hello | LANG= grep '^[ !-~]*$'
hello

I notice that grep command runs fine or not according to NLS environment (my usual LANG value is es_ES.iso88591) but what is NLS-dependant on that match pattern [ !-~] ?

According to ASCII table [ !-~] should be equivalent to [ -~] because "space" char and "!" are consecutive. This range includes all printable 7-bit ASCII characters. Therefore no problems related to NLS should be appear, shouldn't it ?

Re: RE match pattern used in grep command

Elmar P. Kolkman — Thu, 20 Nov 2003 06:01:38 GMT

I am not that experienced with the NLS settings, but I think you also need to check if it is related to the tilde ('~') character...
Just try different patterns for your grep RE to see if it is indeed the ' !' that is causing the problem or the '~' character...

Re: RE match pattern used in grep command

Artyom Voronchihin — Thu, 20 Nov 2003 07:09:36 GMT

Hello !
Not clear understand what are you trying to do. The first of your command (echo hello | grep '^[ !-~]*$') output nothing because where are no any of ^[ !-~]*$ characters in the world "hello". So no matches. The second command you printed assigns string value to $LANG variable. I.e.
# echo hello | LANG=grep'^[ !-~]*$'
output nothing
# echo $LANG
grep^[ !-~]*$

Re: RE match pattern used in grep command

john korterman — Thu, 20 Nov 2003 07:17:15 GMT

Hi,
if grep does not find any of the strange characters it looks for, the if sentence will be true:
if [ "" = "" ]
under which circumstances it says that there is an unprintable character.
Is there not the slightest possibility that a not operator is missing, e.g.:
if [ "`echo $user_info | grep '^[ !-~]*$'`" != "" ]

Just wondering...

regards,
John K.

Re: RE match pattern used in grep command

Jdamian — Thu, 20 Nov 2003 07:47:57 GMT

Hi Artyom. I see you don't understand my question.

1) the match pattern [ !-~ ] means to match any character that is:
a space (ASCII code 32)
or
any char between ! (ASCII code 31) and ~ (ASCII code 126)... this means any ASCII char.

2) There is a space char between the sign = and 'grep' word, then I'm assigning nothing to LANG variable.

I checked LC_COLLATE section in file /usr/lib/nls/loc/src/es_ES.iso885915.src
and found a strange order. Meanwhile order found in C.src is identical to ASCII char, order set in es_ES.iso88591.src doesn't look to be right (perhaps).

I tried another tests:

$ echo hello | LANG= grep '^["-z]*$'
hello
$ echo hello | LANG=es_ES.iso88591 grep '^["-z]*$'
grep: Rango no vÃ¡lido en expresiÃ³n [].

The error messages appears in Spanish.
The translation is:
grep: Invalid range within [] expression.

The same behaviour is found when other values (as it_IT.roman8) for LANG are us

Re: RE match pattern used in grep command

Elmar P. Kolkman — Thu, 20 Nov 2003 08:36:53 GMT

It is solvable by using this pattern:
grep '^[\037-\0176]*$'