topic Re: script to sequence log files in Operating System - HP-UX

script to sequence log files

Vin_4 — Fri, 21 May 2004 05:19:07 GMT

Hi all,

I have a script for sequencing log files from 00 to 59 using:

27 typeset -Z2 N

30 for F in $FILE_LIST
31 do
32 (( N=(N+1)%60 ))
33 mv ${F} $DEST/${N}${F}
34 done

When I run it however I get the following:

./sequence.sh[32]: 08: The specified number is not valid for this command.

Any ideas?

Many thanks.

Re: script to sequence log files

Pete Randall — Fri, 21 May 2004 05:35:17 GMT

Vin,

You might want to look into the Logrotate tool:

http://hpux.cs.utah.edu/hppd/hpux/Sysadmin/logrotate-2.5/

Pete

Re: script to sequence log files

Mark Grant — Fri, 21 May 2004 05:46:01 GMT

This might be the bug that got the posix shell recognizing numbers beginning with 0 as octal.

Try this patch or the latest version of it.

PHCO_29816

Re: script to sequence log files

Juergen Tappe — Fri, 21 May 2004 07:22:15 GMT

Try to change the line :

(( N=(N+1)%60 ))

into :

N=$(( (N+1) % 60 ))

should work...

Re: script to sequence log files

Vin_4 — Fri, 21 May 2004 07:29:48 GMT

Hi all,

thanks for replies so far.

Mark, I think you may be right with that, one system was patched 3 weeks ago (script does not work on this system now), works fine on the un-patched systems.

Maybe changing "typeset" could do the job? any ideas?

Thanks.

Re: script to sequence log files

Mark Grant — Fri, 21 May 2004 07:34:09 GMT

well, I guess changing the "typeset" or just not using it at all would prove if it's the "leading zeros are octal" problem.

If you are having problems though, the solution, as is so often the case, is to simplify. You could go

(( N=N+1 ))
[[ $N -gt 60 ]] && N=0

Re: script to sequence log files

Bharat Katkar — Fri, 21 May 2004 07:37:46 GMT

Hi There,

This worked for me:

For "(( N=(N+1)%60 ))" i did

let N=$N+1
let N=$N/60

Regards,

Re: script to sequence log files

Vin_4 — Fri, 21 May 2004 07:57:03 GMT

Hi Mark,

That's nearly what I need, I have to keep the sequence numbers to 2 digits though.

Is there another way to do this?

Re: script to sequence log files

Mark Grant — Fri, 21 May 2004 08:04:51 GMT

Vin,

If you want to keep it really simple (and nasty) then add this ugly bit in too

(( N=N+1 ))
[[ $N -gt 60 ]] && N=0
[[ $N -le 10 ]] && N="0$N"

Horrible isn't it but if you're having problems why not make it ugly but working in my view :)

Re: script to sequence log files

Vin_4 — Fri, 21 May 2004 09:29:21 GMT

Back to the same problem with the 'ugly' fix unfortunately

27 #typeset -Z2 N

30 for F in $FILE_LIST
31 do
32 (( N=N+1 ))
33 [[ $N -gt 60 ]] && N=0
34 [[ $N -le 10 ]] && N="0$N"

./sequence.sh[32]: 09: The specified number is not valid for this command.

Re: script to sequence log files

John Poff — Fri, 21 May 2004 09:54:18 GMT

Hi,

I think I have your code working. I think the trick is around the typeset command and the octal problem mentioned. I got it to work by using another variable to calculate the number, and then setting the variable N to that number.

Something like this:

typeset -Z2 N
T=0

for F in $FILE_LIST
do
(( T=(T+1)%60 ))
N=$T
mv ${F} $DEST/${N}${F}
done

It looks like your arithmetic expression works, but not with a variable where you have the typeset for -Z2.

JP

Re: script to sequence log files

Bharat Katkar — Fri, 21 May 2004 10:01:24 GMT

typeset -Z2 N=
for F in $FILE_LIST
do
(( N=N+1 ))
[[ $N -gt 60 ]] && N=0
[[ $N -le 10 ]] && N="0$N"

Hope that should work.
Regards,

Re: script to sequence log files

Vin_4 — Mon, 24 May 2004 02:43:39 GMT

That works John, thanks!