topic Re: crontab entries in Operating System - HP-UX

crontab entries

Dave Walley — Mon, 18 Feb 2002 17:24:57 GMT

Hi.

I need to find all lines in crontab files that have numeric values in the first 4 fields (at least). For example I would want the first and third lines returned in this example

00 07 24 7 * /home/ggewrgwer
00 07 * * 2-6 /home/cleanup
00 07 24 7 1-5 /home/ggewrgwer

Any help would be greatly appreciated.

Dave

Re: crontab entries

Krishna Prasad — Mon, 18 Feb 2002 17:37:45 GMT

crontab -l | awk ' $1~/^0-9/ && $2~/^0-9/ && $3~/^0-9/ && $4~/^[0-9/ '

Re: crontab entries

Krishna Prasad — Mon, 18 Feb 2002 17:38:45 GMT

whoops

try this

crontab -l | awk ' $1~/^[0-9]/ && $2~/^[0-9]/ && $3~/^[0-9]/ && $4~/^[0-9]/ '

Re: crontab entries

Volker Borowski — Mon, 18 Feb 2002 17:42:23 GMT

I guess it should read like

awk '{ print ..... }'

Volker

Re: crontab entries

Mark Greene_1 — Mon, 18 Feb 2002 17:43:19 GMT

try a little reverse logic:

crontab -l |grep -v "#"|grep -v "*"|pg

HTH
mark

Re: crontab entries

harry d brown jr — Mon, 18 Feb 2002 17:45:39 GMT

Maybe something like this:

crontab -l | grep "^[0-6]*[0-9] [0-2]*[0-9] [0-3][0-9] [0-9]*[0-9]"

live free or die
harry

Re: crontab entries

Krishna Prasad — Mon, 18 Feb 2002 18:43:07 GMT

FYI-

Don't need the 'print' when you want the entire line to be displayed.

Re: crontab entries

Wodisch — Mon, 18 Feb 2002 18:57:18 GMT

crontab -l |
grep "^[0-9][0-9]* [0-9][0-9]* [0-9][0-9]* [0-9][0-9]* "

or even shorter:

crontab -l |
egep "^[0-9]+ [0-9]+ [0-9]+ [-0]+ "

HTH,
Wodisch