topic Re: shell script in Operating System - Linux

shell script

mougli — Tue, 18 Jul 2006 10:45:46 GMT

Hi,
I have a string like
"ax-a1: xxx@xxx.com yyy@yyy.com zzz@zzz.com;
ax-a2: aaa@aaa.com bbb@bbb.com ccc@ccc.com;"

I need to extract the mailid seperated by a space for any given user like ax-a1.

I have tried to use
Test=`grep a1-ax mailids.txt`
echo $Test | awk '{print substr($0,":",index($0,";"))}'

but it doesn't seem to work. Can you please suggest??

TIA

Re: shell script

Hein van den Heuvel — Tue, 18 Jul 2006 11:04:28 GMT

Hmm,

The second argument to substr is an offset numner, and you passed it a piece of string.
That's not goign to work.

Please explain a little more clearly what you expact for output and where the input comes from.
- A single long string with multiple usernames + email?
- When ax-a1 is select, which are we supposed to return: xxx@xxx.com, or all of "xxx@xxx.com yyy@yyy.com zzz@zzz.com"?

You may readily find a solution by using a regexpr for field seperator. Check out the following example:

$ cat x
ax-a1: xxx@xxx.com yyy@yyy.com zzz@zzz.com; ax-a2: aaa@aaa.com bbb@bbb.com ccc@ccc.com;
$ awk -F'[:; ]+' '{print $3}' x
yyy@yyy.com
$ awk -F'[:;]' '{print $3}' x
ax-a2
$ awk -F'[:;]' '{print $2}' x
xxx@xxx.com yyy@yyy.com zzz@zzz.com

Hope this helps some...
Hein.

Re: shell script

Peter Nikitka — Tue, 18 Jul 2006 11:05:56 GMT

Hi,

if your string has an entry
ax-a1
und you grep for
a1-ax
you won't get results :-)

This will give you the second field stripped by the last character, which is ";" in your case:

awk -F: -v user=ax-a1 '$1 == user {print substr($2,1,length($2)-1)}' mailids.txt

mfG Peter

Re: shell script

Hein van den Heuvel — Tue, 18 Jul 2006 12:42:03 GMT

Buildin up on the external passed usename you could 'walk' the field in steps of 2 looking for a username match.
Note, I had to strip spaces from the username for it to match easily:

$awk -F'[:;]' -v user=ax-a2 '{i=0; while (i++
aaa@aaa.com bbb@bbb.com ccc@ccc.com

Or you could have 'fields' be user:email by using ';' as FS (field seperator) and then splitting on ":" to look at the parts:

$ awk -F\; -v user=ax-a1 '{i=0; while (i++ xxx@xxx.com yyy@yyy.com zzz@zzz.com

Hein.

Re: shell script

James R. Ferguson — Tue, 18 Jul 2006 13:17:29 GMT

Hi:

How about:

# STR="ax-a1: xxx@xxx.com yyy@yyy.com zzz@zzz.com;ax-a2: aaa@aaa.com bbb@bbb.com ccc@ccc.com;"

# echo ${STR} | perl -nle 'BEGIN{$u=shift};print $1 if m/$u:(.+?);/' ax-a1

...would return:

xxx@xxx.com yyy@yyy.com zzz@zzz.com

Regards!

...JRF...

Re: shell script

Sandman! — Tue, 18 Jul 2006 13:34:03 GMT

Here's a way of doing it with sed:

# echo $Test | sed -n 's/$.*$: $.*$;/\2/p'

...and with awk

echo $Test | awk -F": " '{print z[split($2,z,";")-1]}'

Re: shell script

dirk dierickx — Wed, 19 Jul 2006 03:32:04 GMT

cut -d":" -f 2

you'll still have a ';' at the end but that's removed quickly with sed or something similar.

Re: shell script

mougli — Wed, 19 Jul 2006 10:16:53 GMT

Thanks everyone. Got it working now.