topic Awk in Operating System - Linux

Awk

Vanquish — Tue, 13 Jul 2004 17:10:11 GMT

Hi i am trying to get output as
temp
123
lib
resd
com
hp
res
email
html.txt

echo temp/123/lib/resd/com/hp/res/app/email/html.txt| awk '{print substr($0,1)}'

I did try a lot with substr, i tried cut and split too.
echo temp/123/lib/resd/com/hp/res/app/email/html.txt|cut -d / -f1

echo temp/123/lib/resd/com/hp/res/app/email/html.txt|awk '{split('$0',a,"/"); print a[1]}'

Thanks

Re: Awk

K.C. Chan — Tue, 13 Jul 2004 17:17:32 GMT

awk -F"/" {print $1,"\n",$2,"\n", ...}'

Re: Awk

Stuart Browne — Tue, 13 Jul 2004 18:12:31 GMT

So basically you want to replace all /'s with a line feed. 'tr' is the tool for you:

echo temp/123/lib/resd/com/hp/res/app/email/html.txt | tr '/' '\n'

This will put each part of the path on a separate line.

That being said, what's your goal of doing this? If you want to just get the file-name off the end, then just use the 'basename' command.

Re: Awk

Muthukumar_5 — Tue, 13 Jul 2004 23:36:03 GMT

hai,

To do this, use

1. printf "$(echo temp/123/lib/resd/com/hp/res/app/email/html.txt | sed -e 's/\//\\n/g')"

2. echo temp/123/lib/resd/com/hp/res/app/email/html.txt | sed -e 's/\//\
/g'

3. echo temp/123/lib/resd/com/hp/res/app/email/html.txt| awk -F '/' '{
for ( i=1; i<=NF; i++) print $i }'

Regards,
Muthukumar.

Re: Awk

Francisco J. Soler — Wed, 14 Jul 2004 01:39:39 GMT

Hi,

like K.C. Chan but with all fields:

echo temp/123/lib/resd/com/hp/res/app/email/html.txt | awk -F'/' '{for (i=1;i<=NF;i++) print $i}'

Frank.