topic How to replace " by \" in Operating System - Linux

How to replace " by \"

Leo The Cat — Wed, 22 Apr 2009 19:05:36 GMT

Hi Guys

How to replace " by \"

Bests Regards
Den

Re: How to replace " by \"

Matti_Kurkela — Wed, 22 Apr 2009 19:10:00 GMT

In what context?

For example:
$ echo 'by \' | sed -e 's!by \\!something else!g'
something else

MK

Re: How to replace " by \"

Leo The Cat — Wed, 22 Apr 2009 19:21:39 GMT

Hummm example:

Signal=$(myfunccall)

echo $Signal
=> Dump Event "user" sending

java -jar myclass.jar "$Signal_information"
=> I want to have only one parameter here like this

=> Dump Event \"user\" sending

Bests regards
Den

Re: How to replace " by \"

Ivan Ferreira — Wed, 22 Apr 2009 19:44:29 GMT

$ Signal='Dump Event "user" sending'
$ echo $Signal
Dump Event "user" sending
$ echo $Signal | sed 's/"/\\"/g'
Dump Event \"user\" sending

Re: How to replace " by \"

Leo The Cat — Wed, 22 Apr 2009 20:00:38 GMT

Ivan solution is efficient !
Thanks a lot.

Re: How to replace " by \"

Mike Stroyan — Fri, 24 Apr 2009 18:09:44 GMT

The bash printf builtin has a %q format to quote strings for reuse by bash.
It may work well with other parsers.
It will backslash quote characters like spaces, quotes, and ampersands.
Here is an example with %s and %q formats.

$ printf "%s\n" 'try "double quoted" + '"'"'single quoted'"'"' & \t backquoted text'
try "double quoted" + 'single quoted' & \t backquoted text
$ printf "%q\n" 'try "double quoted" + '"'"'single quoted'"'"' & \t backquoted text'
try\ \"double\ quoted\"\ +\ \'single\ quoted\'\ \&\ \\t\ backquoted\ text