topic Re: How to pass a list from the command line in Operating System - Linux

How to pass a list from the command line

Leo The Cat — Mon, 25 May 2009 17:36:19 GMT

Hi

I need to call my script like this:

./myscript.ksh a1001 b1002 c1004 ....

AND

I have to list this with a loop (fow or while). I've tried somethink like that but of course, this does not work.

....
servers=$1
echo "servers: " $servers
USER=test
for i in (`$servers`)
do
echo "\n$i" >> $OUTPUT

sftp $USER@$i < /home/test/bin/oas_replication_cde.txt
done
......

How to do this ?

Thanks a lot
Regards
Den

Re: How to pass a list from the command line

Matti_Kurkela — Mon, 25 May 2009 18:03:58 GMT

When you call a script like this:

./myscript.ksh a1001 b1002 c1004 ...

the parameters are assigned like this:

$1 = a1001
$2 = b1002
$3 = c1004
...

The simplest way to handle this is to use the "shift" command. It moves the parameters so that $2 becomes $1, $3 becomes $2, etc. The old $1 is discarded.

So we can make each parameter in turn be $1 in our loop, and use only $1 for anything we need a parameter for. When $1 becomes empty, we know have processed all the parameters.

USER=test
echo "servers: $*" # all parameters in one

if [ "$1" = "" ]; then
echo "ERROR: no servers listed!"
exit 99
fi

while [ "$1" != "" ]
do
echo "\n$1" >> $OUTPUT
sftp $USER@$1 < /home/test/bin/oas_replication_cde.txt
shift
done

MK

Re: How to pass a list from the command line

Leo The Cat — Mon, 25 May 2009 19:26:57 GMT

Huh

I had closed in a first time this thread but i have an ultimate question .

How to bypass the file oas_replication_cde.txt

That mean going with a full command line without any config or command file

I think this is not possible because how to distinguish command and servers in the parameters ....

Is this (something like that) possible

./myscript.ksh "ls -lrt /tmp" a1001 b1002 c1004

Wher i know that "..." ismy first parameter "!

Bests Regards
Den

Re: How to pass a list from the command line

Dennis Handly — Tue, 26 May 2009 01:29:35 GMT

As Matti said, the standard way to crack the command line is with shift. You can also put them in an array, if no more than 1023:
set -A array_var -- "${@}"

>How to bypass the file oas_replication_cde.txt

What do you mean? You want to exclude that special file if on the command line?

>I think this is not possible because how to distinguish command and servers in the parameters ...

You need to put a special delimiter there or a - option. Or have a fixed count.

>Is this possible
./myscript.ksh "ls -lrt /tmp" a1001 b1002 c1004

Sure. The first parm is "ls -lrt /tmp".

>Where I know that "..." is my first parameter!

You mean starting with $2?

>Matti: When $1 becomes empty, we know have processed all the parameters.
>if [ "$1" = "" ]; then
>while [ "$1" != "" ]; do

The proper test is to check the count of parms, not their value. You can have empty parms.

if [ $# -gt 0 ]; then
while [ $# -gt 0 ]; do

Re: How to pass a list from the command line

Leo The Cat — Tue, 26 May 2009 11:42:13 GMT

Hi Dennis

In fact I'd like to replace < /home/test/bin/oas_replication_cde.txt by the command given in the command line like this:

./myscript.ksh "ls -lrt" a1001 b1002 c1004 ....

I've try this:

...
USER=applopus
echo "servers: $*" # all parameters in one

if [ "$1" = "" ]; then
echo "ERROR: no servers listed!"
exit 99
fi

echo "Command is: "$1

while [ "$2" != "" ]
do
echo "\n$2" >> $OUTPUT
sftp $USER@$i < $1
shift
done

...

But of course the syntaxe is not correct.

Any Idea ?

Best Regards
Den

Re: How to pass a list from the command line

Leo The Cat — Tue, 26 May 2009 12:30:37 GMT

I've try this but not correct

USER=applopus
echo "servers: $*" # all parameters in one

if [ "$1" = "" ]; then
echo "ERROR: no servers listed!"
exit 99
fi

echo "Command is: "$1

while [ "$2" != "" ]
do
echo "\n$2" >> $OUTPUT

sftp $USER@$2 << "EOF"
ls
quit
EOF

shift
done

Re: How to pass a list from the command line

James R. Ferguson — Tue, 26 May 2009 12:37:20 GMT

Hi Den:

Try this:

#!/usr/bin/sh
OUTPUT=/dev/tty
USER=applopus
echo "servers: $*" # all parameters in one
if [ -z "$1" ]; then
echo "ERROR: no servers listed!"
exit 99
fi
CMD=$1
shift
echo "Command is: ${CMD}"
while [ ! -z "$1" ]
do
echo "\n$1" >> $OUTPUT
echo "sftp $USER@$1 < ${CMD}"
shift
done

...

Regards!

...JRF...

Re: How to pass a list from the command line

Leo The Cat — Tue, 26 May 2009 13:44:32 GMT

Hi James

Doesnt work. In fact sftp needs the < with a file. It's curious, but finally I've decided to go with a temporary file (Avoid this should nicest but not so bad) with code like this.

...
echo $1 > /tmp/oas_replication.$$$

while [ "$2" != "" ]
do
sftp $USER@$2 < /tmp/oas_replication.$$$
shift
done

rm -f /tmp/oas_replication.$$$
...

Thanks a lot for all your answers. I've learn again many things by this thread.
Bests Regards
Den

Re: How to pass a list from the command line

Leo The Cat — Tue, 26 May 2009 13:46:40 GMT

Not solved without a temporary file.

Thanks All
Bests Regards
Den

Re: How to pass a list from the command line

Dennis Handly — Sat, 30 May 2009 14:10:30 GMT

>In fact I'd like to replace < .../oas_replication_cde.txt by the command given in the command line like this:
./myscript.ksh "ls -lrt" a1001 b1002 c1004 ....
sftp $USER@$i < $1

You want to echo the command or the output of that command?
You use a pipe:
CMD=$1
...
echo "$CMD" | sftp $USER@$i

>In fact sftp needs the < with a file.

A pipe should work the same.