https://community.hpe.com/t5/operating-system-linux/segmentation-error-with-c-program/m-p/3884478#M67055 "Segmentation violation" means your program is trying to access memory outside the areas reserved to it. With C programs, this usually means you've made some sort of error with pointer variables.<BR /><BR />You should check the number of command line arguments (int argc) before trying to read the argument strings (char **argv).<BR /><BR />The argv is an 1-dimensional array of pointers to strings (1-dimensional arrays of characters): its type can be expressed equivalently as "char **argv", "char *argv[]" or "char argv[][]". I wouldn't recommend the last form though, because it easily leads you to think in the wrong way: argv definitely isn't a two-dimensional array, although it may seem somewhat like it.<BR /><BR />Normally, when you run a program without arguments, argc is usually 1. It means you'll have the name that was used to start the program in *argv[0]. If argc is equal to 1, you must not try to access *argv[1], because argv[1] is either NULL or random nonsense and trying to dereference either of those will produce the error message you're getting.<BR /><BR />In some special situations, the program can be started with argc equal to 0. Never just assume that you can read *argv[0] without checking the value of argc first. Sun, 22 Oct 2006 11:58:57 GMT Matti_Kurkela 2006-10-22T11:58:57Z https://community.hpe.com/t5/operating-system-linux/segmentation-error-with-c-program/m-p/3884477#M67054 Hi guys,<BR /><BR /> I a writing a c program. but whenever try to run the file without arguments it will give segmentation. How can I catch this error before it terminate the progam. Thanks.<BR /><BR />Best regards<BR />Henry Sun, 22 Oct 2006 06:20:32 GMT https://community.hpe.com/t5/operating-system-linux/segmentation-error-with-c-program/m-p/3884477#M67054 Henry Chua 2006-10-22T06:20:32Z https://community.hpe.com/t5/operating-system-linux/segmentation-error-with-c-program/m-p/3884478#M67055 "Segmentation violation" means your program is trying to access memory outside the areas reserved to it. With C programs, this usually means you've made some sort of error with pointer variables.<BR /><BR />You should check the number of command line arguments (int argc) before trying to read the argument strings (char **argv).<BR /><BR />The argv is an 1-dimensional array of pointers to strings (1-dimensional arrays of characters): its type can be expressed equivalently as "char **argv", "char *argv[]" or "char argv[][]". I wouldn't recommend the last form though, because it easily leads you to think in the wrong way: argv definitely isn't a two-dimensional array, although it may seem somewhat like it.<BR /><BR />Normally, when you run a program without arguments, argc is usually 1. It means you'll have the name that was used to start the program in *argv[0]. If argc is equal to 1, you must not try to access *argv[1], because argv[1] is either NULL or random nonsense and trying to dereference either of those will produce the error message you're getting.<BR /><BR />In some special situations, the program can be started with argc equal to 0. Never just assume that you can read *argv[0] without checking the value of argc first. Sun, 22 Oct 2006 11:58:57 GMT https://community.hpe.com/t5/operating-system-linux/segmentation-error-with-c-program/m-p/3884478#M67055 Matti_Kurkela 2006-10-22T11:58:57Z