topic Re: Abnormal if condition behavior in script. in Operating System - Linux

Abnormal if condition behavior in script.

Nuwan Wijesundera — Tue, 09 Mar 2004 09:31:01 GMT

Hi all,
I input the attached file to the following script.
+++++++++++++++++++++++++++++++++++++++++++++
#!/bin/bash
num="`awk '/X-MailRelay-ToCount/{print $2}' $1`"
echo $num
if test "${num}" = "1"
then
echo num eq to 1
else
echo num not eq to 1
fi
exit
++++++++++++++++++++++++++++++++++++++++++++
But when I execute the script it doesn't not output the desired output.
Means when $num =1, it should output "num eq to 1" ,BUT it outputs the else part.

Please help me to resolve this abnormal behavior.Any modifications to the script.
Big thank.

Re: Abnormal if condition behavior in script.

Alexander Chuzhoy — Tue, 09 Mar 2004 09:46:48 GMT

I think you should have == instead of =
in this line:
if test "${num}" = "1"

I mean you want to say if it's equal then do something.
In your script it says it's equal .
Not that I'm great with bash scripts...

Re: Abnormal if condition behavior in script.

Mark Grant — Tue, 09 Mar 2004 10:47:24 GMT

Alexander is obviously good enough with bash scripts :)

He has your error :)

P.S. No points for this one please.

Re: Abnormal if condition behavior in script.

Olivier Drouin — Tue, 09 Mar 2004 14:38:18 GMT

for example...
you use == for string comparison.
you use -eq for integer comparison.

Re: Abnormal if condition behavior in script.

Penguin_1 — Tue, 09 Mar 2004 15:12:30 GMT

use this
if [ ${num} -eq 1 ]; then
.....

penguin