topic Re: for loop help in Operating System - Linux

for loop help

lawrenzo_1 — Fri, 01 Feb 2008 16:37:13 GMT

Hi,

I want to manipulate some data ie:

oldgemp016 to oldgemp030

I need to make these not mountable on system reboot (AIX) and the command line is

chfs -A n oldgemp

how would I sort the regular expression in a for loop??

I am kinda thinking I should

for a in `echo oldgemp0[1-3][0-9]`

however this will error on gemp010 11 12 etc becuase they dont exist.

how could this be resolved?

any help is greatly appreciated as always.

Thanks

Chris.

Re: for loop help

Ralph Grothe — Fri, 01 Feb 2008 17:06:25 GMT

There are many possibilities.
Will this one do?

$ i=15;while (($((i+=1))<=30));do echo oldgemp0$i;done
oldgemp016
oldgemp017
oldgemp018
oldgemp019
oldgemp020
oldgemp021
oldgemp022
oldgemp023
oldgemp024
oldgemp025
oldgemp026
oldgemp027
oldgemp028
oldgemp029
oldgemp030

Re: for loop help

lawrenzo_1 — Fri, 01 Feb 2008 17:20:48 GMT

thats great

many thanks

chris

Re: for loop help

Peter Nikitka — Fri, 01 Feb 2008 17:33:39 GMT

Hi,

I think there is a 'lsfs' on AIX, and I'm shure it was enough options to restrict its output to a parsable form.
Then something like
for in in `lsfs `
do
...
done

or
for in in `lsfs | grep oldgemp0[1-3][0-9]`
do
...
done

will present you only existing volumes.

mfG Peter

Re: for loop help

lawrenzo_1 — Fri, 01 Feb 2008 17:51:13 GMT

here is an example using the lsfs command

thanks Peter for the prompt

for FS in `lsfs -c |awk -F':' '/oldgemp/ {print $1}' |sed 's/\/app\///'`
do
etc etc

again another example however if I was looking for regular expression to find all values for oldgemp016 to oldgemp030

what would be the best systax?

thanks

Chris

Re: for loop help

James R. Ferguson — Fri, 01 Feb 2008 18:11:01 GMT

Hi Chris:

> if I was looking for regular expression to find all values for oldgemp016 to oldgemp030

You could use:

# awk '/oldgemp0[1][6-9]|[2][0-9]|30/'

Regards!

...JRF...

Re: for loop help

lawrenzo_1 — Mon, 04 Feb 2008 10:54:01 GMT

ok good - thanks all

Re: for loop help

Dennis Handly — Wed, 06 Feb 2008 07:01:43 GMT

>JRF: # awk '/oldgemp0[1][6-9]|[2][0-9]|30/'

I don't think the operator precedence is correct for your ERE. You need:
$ awk '/oldgemp0([1][6-9]|[2][0-9]|30)/'

Your first one finds "new20".

Re: for loop help

James R. Ferguson — Wed, 06 Feb 2008 12:49:42 GMT

Hi:

>Dennis: JRF I don't think the operator precedence is correct for your ERE

Good catch, thanks. You are correct, of course.

Regards!

...JRF...