topic Re: Using "cut" for field "N" thru the "last" field in Operating System - Linux

Using "cut" for field "N" thru the "last" field

john guardian — Fri, 21 Sep 2007 13:29:51 GMT

Isn't there a method for using cut to grab, for instance, the 3rd thru the "remaining" fields in a space delimited string.

String example: ExStr="One 2 three for"

Let's say I want "all fields beyond field 2 (3-end of the string). Doesn't cut work with some limited set of wildcards for this...

IE: echo $ExStr | cut -f 3- -d " "

Re: Using "cut" for field "N" thru the "last" field

larsoncu — Fri, 21 Sep 2007 13:35:24 GMT

3- would specify 3 thru the last

Re: Using "cut" for field "N" thru the "last" field

Sandman! — Fri, 21 Sep 2007 13:37:25 GMT

# echo "one two three four five six seven eight nine" | cut -f3- -d" "

Re: Using "cut" for field "N" thru the "last" field

john guardian — Fri, 21 Sep 2007 13:39:23 GMT

Thanks.