topic Print all lines after a line with given string in Operating System - Linux

Print all lines after a line with given string

Jeff_Traigle — Fri, 16 Mar 2007 11:23:07 GMT

Trying to extract the device files for mirrors from lvdisplay. This works, but I'm thinking there must be a slightly better command string to do it:

lvdisplay -v ${LV} | awk '/LE PV1/,EOF' | grep -v "LE PV1" | awk '{print $2, $5}' | sort -u

Re: Print all lines after a line with given string

Pete Randall — Fri, 16 Mar 2007 11:50:55 GMT

Jeff:

From "Handy one-liners for SED" (attached):

# print section of file from regular expression to end of file
sed -n '/regexp/,$p'

Pete

Re: Print all lines after a line with given string

James R. Ferguson — Fri, 16 Mar 2007 12:01:36 GMT

Hi Jeff:

# lvdisplay -v ${LV} | perl -nle 'if (/0000/../ /){@a=split;$dev=$a[1]." ".$a[4];$m{$dev}++};END{for (sort keys %m) {print}}'

Regards!

...JRF...

Re: Print all lines after a line with given string

Peter Nikitka — Fri, 16 Mar 2007 12:01:40 GMT

Hi,

an awk suggestion:
lvdisplay -v ... |
awk '/LE PV1/ {out=1;next}
out {print $2,$5}' |
sort -u

mfG Peter

Re: Print all lines after a line with given string

Jeff_Traigle — Fri, 16 Mar 2007 13:08:21 GMT

Thosee awk and perl solutions worked. Of course, seeing JRF's test for LE 00000 made me realize I was making it too difficult to start with... the first LE in an LV is always going to be 00000 so simplifies life looking for that instead of the column headers. (My mind was already on vacation, I guess.) This compressed awk option works fine too.

/usr/sbin/lvdisplay -v ${LV} | awk '/00000/,EOF {print $2, $5}' | sort -u