The radius of image of a circle under mobius transformation

ObviousKiwi — Wed, 11 Aug 2021 12:04:08 GMT

A Mobius transformation of the plane takes z↦az+bcz+d. These are known to take circles to circles, but given an explicit circle, how do we compute the radius.

Let's parameterize our circle by z(t)=z0+re2πint. What is the radius and center of the image circle?

az(t)+bcz(t)+daz(t)+bcz(t)+d

I am looking for a computational proof that the image is a circle so I can find the (Euclidean) radius and centerIn my application, I have an approximate circle {z0+e2πint:t∈1NZ} where N is a large number. If we act the Mobius transformation pointwise, these spaces will no longer be evenly spaced out. So I decided it's better to compute the Euclidean center and radius if possible.

Re: The radius of image of a circle under mobius transformation

Ivan_B — Wed, 11 Aug 2021 12:07:01 GMT

Hello @ObviousKiwi !

It's really fascinating what you are doing, but how is it related to the HPE Networking?

topic The radius of image of a circle under mobius transformation in Software Defined Networking

The radius of image of a circle under mobius transformation

Re: The radius of image of a circle under mobius transformation