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тАО11-04-2009 03:34 AM
тАО11-04-2009 03:34 AM
Re: Problems with or operator
Getting Syntax error at line 11 : `-a' is not expected for the below code
if [ "$1" != "Trail" -a "$1" != "Image" ];
if [[ "$1" != Trail && "$1" != Image ]];
Thanks
Suneeth
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тАО11-04-2009 03:41 AM
тАО11-04-2009 03:41 AM
Re: Problems with or operator
All of them are working. I missed to take a comment on one of the condition.
Thanks for all.
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тАО11-04-2009 05:54 AM
тАО11-04-2009 05:54 AM
Re: Problems with or operator
if [[ "$1" != Trail -a "$1" != Image ]]
The intention was I want the parameter either Trail or Image. If it is trail do something or Image do something. I thought `and` will always check both conditions."
uh... in that case, I'd have thought something like
if [[ "$1" = Trail -o "$1" = Image ]]
would have been more appropriate, as you seem to be stating you want $1 to be either Trail or Image.
The test you posted will NOT run anything if $1 is "Trail" or "Image" but would run if $1 were, say, "Junk"
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тАО11-04-2009 06:08 AM
тАО11-04-2009 06:08 AM
Re: Problems with or operator
"The intention was I want the parameter either Trail or Image. If it is trail do something or Image do something. I thought `and` will always check both conditions."
# if $1 is Trail or Image, it echoes found #.
echo $1
if [ "$1" = "Trail" -o "$1" = "Image" ]; then
echo "found 1"
fi
if [[ "$1" = Trail || "$1" = Image ]]; then
echo "found 2"
fi
[ "$1" = Trail ] || [ "$1" = Image ] && echo "found 3"
one of the many answers above should match what you are attempting to do. But since you state one case, then choose the logic for the other, it's really tough to tell what the heck you really want
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тАО11-05-2009 01:16 AM
тАО11-05-2009 01:16 AM
Re: Problems with or operator
if [[ "$1" = Trail -o "$1" = Image ]]
would have been more appropriate, as you seem to be stating you want $1 to be either Trail or Image.
The test you posted will NOT run anything if $1 is "Trail" or "Image" but would run if $1 were, say, "Junk"
-------------------------------
This is where i used my condition. Did i construct the code badly ?
if [ "$1" != "Trail" -a "$1" != "Image" ]; then
echo "Check the case"
exit
fi
#Then I start with statements for the parameter
while [ $1 == Trail ]
do
done
while [ $1 == Image ]
do
done
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тАО11-05-2009 02:26 AM
тАО11-05-2009 02:26 AM
Re: Problems with or operator
if [ "$1" != "Trail" -a "$1" != "Image" ]; then
echo "Check the case"
exit
fi
This seems fine.
>#Then I start with statements for the parameter
while [ "$1" == Trail ]; do
I'm not sure why you want a while, instead of just an if. Do you use shift to get the next parm?
You may want to use a case:
case "$1" in
Trail) ... ;;
Image) ... ;;
*) echo "Check the case"
exit
;;
esac
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тАО11-05-2009 06:37 AM
тАО11-05-2009 06:37 AM
Re: Problems with or operator
There is no loop in my code hence case is the right one.
I can cover this in if, but I will have some more conditions to check and I found this will be easier.
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тАО11-05-2009 07:53 AM
тАО11-05-2009 07:53 AM
Re: Problems with or operator
My confusion revolved around your statement(s) like:
"The intention was I want the parameter either Trail or Image. If it is trail do something or Image do something. I thought `and` will always check both conditions."
-AND- the illustrated "IF" test
if [ "$1" != "Trail" -a "$1" != "Image" ]; then
After seeing your code snippet, I'd have said that your intention was to check if $1 was either "Trail" or "Image", and stop if not. This became clear when you posted some addtional code.
"if [ "$1" != "Trail" -a "$1" != "Image" ]; then
echo "Check the case"
exit
fi"
Actual code posted seems to be just fine. As Dennis noted, "case" may be a more elegant solution, or it have been written as series of if/elseif/elseif...statements.
In any event, sorry for the confusion.
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тАО11-06-2009 12:54 AM
тАО11-06-2009 12:54 AM
Re: Problems with or operator
As i stuck with If syntax i just want to know the whats issue is. As you said its always better to give more information instead of pasting it a single line code.
This will help others to give thier inputs correctly.
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