entering charcter or numerical value then checking

[Mel Burslan]

Then maybe, instead of blindly posting questions in other UNIX platforms' forums, like HPUX here, you might want to try some linux forum. Huh ?

[lcpdl87]

and extra credit is not homework. it's something you choose to do if you more points to your grade and its OPTIONAL. it's not actual homework. homework is required to get the grade. I'm just trying to do this to boost my grade up alittle.

[James R. Ferguson]

Hi:

> Well, if I wasn't stuck, I wouldn't even bother checking this site for help. It's a forum, you post your problem and people help you out.

Yes, in principal. However, this community is intended to be for professionals dealing with professional problems, not for homework questions. You are more than welcome to lurk and learn.

Regards!


...JRF...

[OldSchool]

"No, its extra credit, ..." that's homework

the version Mel posted works just fine w/ ksh and sh (after adding quotes around the []), has a few issues w/ echo in bash and dash

it appears that you missed some whitespace around the "%", but its hard to tell in the posts

original was:
...
result=$(($num % 2))
if [ $result -eq 0 ]
....


you posted:
...
the "result=$(($num %2))
if[$result -eq 0]
...

[James R. Ferguson]

Hi:

I meant to say "Yes, in principle". You see the _principal_ users here are professionals with professional needs, not students doing homework.

...JRF...

[OldSchool]

there are a variety of shell tutorials available. parker's site is useful, as is shelldorado.

one thing I would caution you about is learning scripting on linux (ie. bash) and then attempting to use unix. the "linuxy" gnu extensions that you will come to expect simply won't be there.

ksh tends to port well from unix to linux, and visa versa.

[Dennis Handly]

>I'm working with Linux 10

(I'll ask the moderators to move it there with your other thread.)

>OldSchool: original was:
>result=$(($num % 2))

There is no need to use "$" within (( )) or $(( )).
(( result = num % 2 ))

In fact, you can replace the original by:
if (( number % 2 == 0 )); then

[ghostdog74]

#!/bin/bash
awk 'BEGIN{
while(1){
printf "Enter a numerical number: "
getline number < "/dev/stdin"
if (number+0==number){
print "yes, a number"
break
}else{
print "no, not a number. Enter again"
}
}
print "number is " number
if ( number %2 == 0 ){
print "Number "number" is even"
}else{
print "Number "number" is odd"
}
}'

[lcpdl87]

I tested that. That makes it say there's no file or directory for the file.

[ghostdog74]

it works fine for me.