grep bdf for aavail > number

[Warren Cook_2]

Hello all,

Would like to know how to perform bdf, grep on 'avail' column for all filesystems greater than a given size. Also want to display all columns from bdf.
So far below cmd prints all fields (no spaces) but picks only one record from bdf (the matching one, I want to test for all > 4000000):
bdf|tr -s " " ||awk '{print $1 $2 $3 $4}'cut -f 2 -d " " |grep 4000000

thx

[Pete Randall]

Warren,

I'm reasonable certain I've seen something like this before and I'm willing to bet that I saw it in one of Bill McNamara's "Favorite Scripts" threads. Here's the first one, which also provides links to the other two. Have a look through them. Even if you don't find exactly what you're looking for, they're an invaluable resource.

http://forums1.itrc.hp.com/service/forums/questionanswer.do?threadId=51050


Pete

[Peter Day_2]

Warren,
Try this -

for a in $(bdf |awk '{print $4}')
do
if [[ "$a" != "avail" ]]
then
if [[ $a -gt 4000000 ]]
then
echo Bigger than 4000000
fi
fi
done

Hope this works, it did on my system.
Regards,
Pete


.

[RAC_1]

bdf|awk '{if($4>=106000) print $4}'

[Steve Steel]

Hi

Since for long file system names bdf uses 2 lines this is difficult to realise easily

df -n|cut -f2 -d"("|cut -f1 -d ")"|while read line
do
xx=$(bdf $line|tail -n +2)
echo $xx|while read a b rest
do
let val=$b
if [ "$val" -gt "4000000" ]
then
echo $xx
fi
done
done|sort -n


Steve Steel

[Mark Greene_1]

Try this:

IZE=512000
OLDIFS=$IFS
IFS="
"
for LINE in `bdf`; do
FIELD2=`echo $LINE|tr -s " "|awk '{print $2 }'`
FS_SIZE=`echo $FIELD2|tr -d "[:alpha:]" `
if [[ "$FS_SIZE" -ge $SIZE ]]; then
echo $LINE
fi
done

[Warren Cook_2]

Thank-you all for great and quick feedback ! I've tried all suggestions and will assign points shortly.

Mark, I'm using your suggestion, I can't get the IF to work. It appears to be comparing strings and always gives a true answer, so all bdf records are printed. I've tried several variations with no luck ... if you or anyone has a suggestion.

I mean this if:
if [[ "$FS_SIZE" -ge $SIZE ]]; then

thx

[Kent Ostby]

bdf | awk '$2>4000000'

[Sridhar Bhaskarla]

Hi,

bdf is not my favorite for checking the utilizations due to below warning from the man page of bdf.

WARNINGS
If file system names are too long, the output for a given entry is
displayed on two lines.

This can confuse your script quite a bit. So, I would write the script using 'df' something like this

LIMIT=100000

cleanup()
{
rm -f /tmp/fs$$ /tmp/fsreport$$
}

trap cleanup 0 1 2

for FS in $(df -l|awk '{print $1}')
do
AVAIL=$(df -k $FS|awk '/free allocated Kb/ {print $1}')
if [ $AVAIL -ge $LIMIT ]
then
bdf $FS |sed '1d'
fi
done


Adjust your if's and limits accordingly.

-Sri

[Kent Ostby]

oops .. missed the "no spaces part"

bdf | tr -s " " | awk '$2>4000000'