list in order of size of file

[bob the spod]

is there a way i can do a list to bring up the contents of a directory ranked by data size?
Preferbly I would like the largest files at the bottom of the list
it will save me a lot of time searching by a letter at a time!
cheers
bob

[Dietmar Konermann]

ll | sort -rnk 5

[Dietmar Konermann · Accepted solution]

Sorry... at the bottom. :)
ll | sort -nk 5

[steven Burgess_2]

Hi

ll | sort -nk5

To reverse

ll | sort -rnk5

HTH

Steve

[Uday_S_Ankolekar]

Go to the directory
du -sk * | sort -n

-USA..

[Rodney Hills]

Usually I do a-
ll | sort -n -r +4 -5 | more

This way I see the largest files first. If you drop "-r" then it will be smallest size first.

Another good utility to use is "du". It can do totallying on subdirectories as well. A common practice I use is.

cd /somepath
du -s * | sort -n | more

To find the largest subdirectories in the current directory.

HTH

-- Rod Hills