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05-16-2004 10:15 PM
05-16-2004 10:15 PM
set -A VAR -g reports an error message
Hi
'set -A' is used to declare and fill an array variable.
The following example works fine:
set -A VAR A B "C D"
but this other reports an error message:
set -A VAR -g
/usr/bin/sh: -g: bad option(s)
why '-g' is seen as an option by shell ?
According to manual pages remaining args after variable name are the values to be assigned. But I suspect shell parses them and reports errors because changing character after dash reports other error messages:
set -A VAR -A
/usr/bin/sh: -A: argument expected
The next example sets properly VAR2:
set -A VAR -A VAR2 hello people
The next example sets properly VAR:
set -A VAR '\-A' VAR2
The next example sets no variable:
set -A VAR -
Is this a bug ?
Thanx in advance
'set -A' is used to declare and fill an array variable.
The following example works fine:
set -A VAR A B "C D"
but this other reports an error message:
set -A VAR -g
/usr/bin/sh: -g: bad option(s)
why '-g' is seen as an option by shell ?
According to manual pages remaining args after variable name are the values to be assigned. But I suspect shell parses them and reports errors because changing character after dash reports other error messages:
set -A VAR -A
/usr/bin/sh: -A: argument expected
The next example sets properly VAR2:
set -A VAR -A VAR2 hello people
The next example sets properly VAR:
set -A VAR '\-A' VAR2
The next example sets no variable:
set -A VAR -
Is this a bug ?
Thanx in advance
1 REPLY 1
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05-17-2004 12:17 AM
05-17-2004 12:17 AM
Re: set -A VAR -g reports an error message
Try this:
set -A VAR "\-g"
set -A VAR "\-g"
"Well, actually, she is a rocket scientist" -- Steve Martin in "Roxanne"
The opinions expressed above are the personal opinions of the authors, not of Hewlett Packard Enterprise. By using this site, you accept the Terms of Use and Rules of Participation.
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