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тАО10-20-2003 02:03 AM
тАО10-20-2003 02:03 AM
HP 9000 Superdome heat dissipation
We may also be getting an xp1024 Disk Array. Anyone have the heat disipation on this unit?
Thanks,
Joe McCauley
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тАО10-20-2003 04:39 AM
тАО10-20-2003 04:39 AM
Re: HP 9000 Superdome heat dissipation
this should be in the "Superdome Site Preparation Guide" A5201-10024
on http://docs.hp.com
see attachment
Regards,
Bernhard
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тАО10-20-2003 05:06 AM
тАО10-20-2003 05:06 AM
Re: HP 9000 Superdome heat dissipation
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тАО10-20-2003 11:20 AM
тАО10-20-2003 11:20 AM
Re: HP 9000 Superdome heat dissipation
You have to realize that for all practical purposes (and to greater than 99.9% accuracy) computers are nother but heaters -- expensive heaters but heaters nonetheless.
This means that if you have the input power, you have the output head dissipation --- they are one in the same.
To approximate power dissipation, you can multiply rated input voltage by rated current to get Volt-Amps. Then multiply by a power factor (usually about 0.8 to get watts - remember this is AC 1VA is usually not 1WA because we have those pesky phase angles) If you want to be very conservative, use a pf of 1.0 and some HP computers run a pf of 0.99. If you use a power factor of 1.0 then you will always be safe. The one other formula I should throw at you is how to calculate 3-phase power. It's simply P = IV * 3 ^ 0.5 * pf where P = power in watts, I = current in Amperes, V = Voltage, 3 ^ 0.5 ==> square root of 3 (or the appropriate number of phases), and pf = power factor (again somewhere between 0.8 and 1.0). Power factor is actually the cosine of the between the phase angle of the current and voltage.
Example :
Suppose the power supply label indicates 10 A at 200V; what is the thermal dissipation?
10A x 200V = 2000VA x 0.8 (pf) = 1600W.
1600W x 3.412 BTU/HR-W = 5460 BTU/HR.
The other conversion factor you need to know is that 12000 BTU/hr = 1Ton Cooling Capacity
Regards, Clay
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тАО10-19-2004 01:41 AM
тАО10-19-2004 01:41 AM