- Community Home
- >
- Storage
- >
- HPE Nimble Storage
- >
- HPE Nimble Storage Solution Specialists
- >
- Re: Usable Capacity calculation
-
-
Forums
- Products
- Servers and Operating Systems
- Storage
- Software
- Services
- HPE GreenLake
- Company
- Events
- Webinars
- Partner Solutions and Certifications
- Local Language
- China - 简体中文
- Japan - 日本語
- Korea - 한국어
- Taiwan - 繁體中文
-
- Advancing Life & Work
- Advantage EX
- Alliances
- Around the Storage Block
- HPE Ezmeral: Uncut
- OEM Solutions
- Servers & Systems: The Right Compute
- Tech Insights
- The Cloud Experience Everywhere
- HPE Blog, Austria, Germany & Switzerland
- Blog HPE, France
- HPE Blog, Italy
- HPE Blog, Japan
- HPE Blog, Middle East
- HPE Blog, Latin America
- HPE Blog, Russia
- HPE Blog, Saudi Arabia
- HPE Blog, South Africa
- HPE Blog, UK & Ireland
- HPE Blog, Poland
-
Blogs
- Advancing Life & Work
- Advantage EX
- Alliances
- Around the Storage Block
- HPE Blog, Latin America
- HPE Blog, Middle East
- HPE Blog, Saudi Arabia
- HPE Blog, South Africa
- HPE Blog, UK & Ireland
- HPE Ezmeral: Uncut
- OEM Solutions
- Servers & Systems: The Right Compute
- Tech Insights
- The Cloud Experience Everywhere
-
Information
- Community
- Welcome
- Getting Started
- FAQ
- Ranking Overview
- Rules of Participation
- Tips and Tricks
- Resources
- Announcements
- Email us
- Feedback
- Information Libraries
- Integrated Systems
- Networking
- Servers
- Storage
- Other HPE Sites
- Support Center
- Aruba Airheads Community
- Enterprise.nxt
- HPE Dev Community
- Cloud28+ Community
- Marketplace
-
Forums
-
Forums
-
Blogs
-
Information
-
English
- Subscribe to RSS Feed
- Mark Topic as New
- Mark Topic as Read
- Float this Topic for Current User
- Bookmark
- Subscribe
- Printer Friendly Page
- Mark as New
- Bookmark
- Subscribe
- Mute
- Subscribe to RSS Feed
- Permalink
- Report Inappropriate Content
11-15-2020 11:04 PM
11-15-2020 11:04 PM
Hi Team,
if you have twelve 4TB drives installed into an array, the raw space is 48TB (12TB * 4 = 48TB) In this example, we have 48TB of Raw Capacity. From that we subtract all overhead associated with RAID Triple parity we can see 36TB but one of the document says that 33TB am not sure howmuch other capacity used for other matics like volume reservations, system spares etc to make 33TB usable?
Solved! Go to Solution.
- Mark as New
- Bookmark
- Subscribe
- Mute
- Subscribe to RSS Feed
- Permalink
- Report Inappropriate Content
11-18-2020 12:14 AM
11-18-2020 12:14 AM
Re: Usable Capacity calculation
You should refering to the old gen adaptive flash CSxxx, which comes with 4 x SSD and 12 x NL-SAS.
4TB drive is marketing figure and in fact it doesn't shiped with 4TB disk blocks.
Therefore, by reducing 3 drives for standard triple parity, plus system reserve and checksum, it gives 33TB usable. But with compression is always ON, and based on the common data types in actual deployement we see, effective capacity should always yields more than that.
Thomas Lam - Global Storage Field CTO
I work for HPE

- Mark as New
- Bookmark
- Subscribe
- Mute
- Subscribe to RSS Feed
- Permalink
- Report Inappropriate Content
11-18-2020 05:00 AM - edited 11-18-2020 05:24 AM
11-18-2020 05:00 AM - edited 11-18-2020 05:24 AM
SolutionNimble Array Models such as AF20/AF40/AF60/AF80 require minimum 24 drives.
Nimble Array Models such as HF20/HF20C/HF40/HF40C/HF60 require minimum 3 SSD + 21 NL-SAS drives.
Nimble Array HF20H require minimum 1 SSD + 11 NL-SAS drives
Nimble Array AF20Q is the one which can work with only 12 SSD drives.
If you are talking about 12 drives, I guess you must be talking about AF20Q. In AF-series Arrays, we have spare chunks in every drive which will never be used for storing Data or Parity. It is used for storing reconstructed data when a drive fails.
Out of 12 drives, 1 drive worth of space is marked as Spare chunks (Distributed Sparing). So you are left with space equal to 11 drives.
In your example, each drive is 4 TB. So total RAW space available for Data + Parity is 4 X 11 = 44 TB
When you start creating Volumes, Nimble Array Controller will create so many RAID sets with set size (8 + 3).
Now, If you Calculate...For every 8 GB of Data written -> 3 GB of space is required for Parity.
So out of 44 TB of RAW space, how much will be for Data & how much for Parity?
Approx, 32 GB for Data + 12 GB for Parity.
I work for HPE
Hewlett Packard Enterprise International
- Communities
- HPE Blogs and Forum
© Copyright 2022 Hewlett Packard Enterprise Development LP